请问如何提取一个文本中两行已知内容之间的内容。
比如在某hosts文件中存在如下内容。
……
Localhost (DO NOT REMOVE)
127.0.0.1 localhost
255.255.255.255 broadcasthost
::1 localhost
fe80::1%lo0 localhost
Modified hosts start
……
我想要提取“Localhost (DO NOT REMOVE)”和“Modified hosts start”中的内容到另外一个文本中。
应该怎么解决呢?我使用的如下代码哪里有问题呢?
char str[256],start1[256],end1[256];
strcpy(start1,"# Localhost (DO NOT REMOVE)");
strcpy(end1,"# Modified hosts start");
while (!feof(fstream_backup)){
fgets(str,1024,fstream_backup);
if (strcmp(str, start1)==0){
while (strcmp(str, end1)!=0){
fgets(str,1024,fstream_backup);
fprintf(fstream_out,"%s",str);
}
}
}
谢谢。
黄舟2017-04-17 14:02:33
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int main()
{
bool flag = false;
ifstream file1("file1.txt");
ofstream file2("file2.txt");
string line, des1("Localhost (DO NOT REMOVE)"), des2("Modified hosts start");
while (getline(file1, line)) {
if (line == des1) {
flag = true;
continue;
}
if (line == des2)
break;
if (flag)
file2 << line << endl;
}
file1.close();
file2.close();
}
Since it is under C++, it is recommended to write it like this.
PHP中文网2017-04-17 14:02:33
Why do you need to use such a cumbersome language like c++? The shell can handle it elegantly
The following statement can output the text between line1 and line5
cat file1 | sed -n /line1/,/line2/p | sed /line1/d | sed /line2/d > file2