就像图片中所示的这样,找出table2和table3相对于table1 的缺失值。
右下角的表格是想要查询出来的结果。
跪求各位大神帮忙!!!
伊谢尔伦2017-04-17 13:08:49
SQL can’t do this. The values 2-4 and 2-8 in the result columns of your query do not exist in the database. How do you query the database for values that do not exist in the database? So I think your table structure Do you need to change it? The ID column is just an ID without adding a prefix.
sql
DROP TABLE IF EXISTS table1; DROP TABLE IF EXISTS table2; DROP TABLE IF EXISTS table3; CREATE TABLE table1 (id INT NOT NULL PRIMARY KEY, name VARCHAR(20)); CREATE TABLE table2 (id INT NOT NULL PRIMARY KEY, name VARCHAR(20)); CREATE TABLE table3 (id INT NOT NULL PRIMARY KEY, name VARCHAR(20)); INSERT INTO table1 VALUES(1, 'ACF'); INSERT INTO table1 VALUES(2, 'DEF'); INSERT INTO table1 VALUES(3, 'QWE'); INSERT INTO table1 VALUES(4, 'RTY'); INSERT INTO table1 VALUES(5, 'UIO'); INSERT INTO table1 VALUES(6, 'OPL'); INSERT INTO table1 VALUES(7, 'ASD'); INSERT INTO table1 VALUES(8, 'FGH'); INSERT INTO table1 VALUES(9, 'ZXC'); INSERT INTO table2 VALUES(1, 'ACF'); INSERT INTO table2 VALUES(2, 'DEF'); INSERT INTO table2 VALUES(3, 'QWE'); INSERT INTO table2 VALUES(5, 'UIO'); INSERT INTO table2 VALUES(6, 'OPL'); INSERT INTO table2 VALUES(7, 'ASD'); INSERT INTO table2 VALUES(9, 'ZXC'); INSERT INTO table3 VALUES(1, 'ACF'); INSERT INTO table3 VALUES(3, 'QWE'); INSERT INTO table3 VALUES(4, 'RTY'); INSERT INTO table3 VALUES(7, 'ASD'); INSERT INTO table3 VALUES(8, 'FGH'); INSERT INTO table3 VALUES(9, 'ZXC'); -- 结果查询 SELECT id, name FROM table1 WHERE id NOT IN (SELECT id FROM table2) UNION SELECT id, name FROM table1 WHERE id NOT IN (SELECT id FROM table3);