string str ="123456";
如何把str的每一位str[i]转换成数字?
已经尝试:
用int(str[i])只能得到ascii码。
用atoi(str.c_str())也只能将整个string转换成int。
怪我咯2017-04-17 13:00:45
You have already got the ASCII code, isn’t it just a number after subtracting ‘0’ (that is, 48)...
迷茫2017-04-17 13:00:45
#include <string>
#include <stdlib.h>
using namespace std;
int main(){
string str = "123456";
const char *p = str.c_str();
for (int i = 0; i < str.length(); i++)
{
int a = str[i] - '0';
printf("%d \n", a);
}
system("pause");
return 0;
}