C++的拷贝构造，指针释放问题

Question

先上代码，no code no say

/*
class Point{
//...
};
*/
Point *pPoint = new Point;    //1
Point point;                  //2                
*pPoint = point;              //3
//...
delete pPoint                 //4

关于步骤1new可分解为如下：

//cpp为代码
Point *pPoint = __new( sizeof(Point));   //5
if(pPoint)
{
    pPoint->Point::Point();
}

步骤3，是不是就是调用Point的拷贝赋值函数？
步骤4删除该指针就是针对步骤5进行分配的内存进行释放？
我这样理解是否有错？

Answer 1

The understanding of step 3 is basically correct. Step 4 not only releases the memory, but also executes the destructor before that, which is basically equivalent to pPoint->Point::~Point();

Answer 2

Excuse me, after executing step 5, isn’t this memory still not released?

Answer 3

There is no problem in understanding step 3, and there is no problem in step 4, but pPoint = NULL should be added. Because your delete just tells the program that I don't want this pointer anymore. After the memory is released, the pointer still points to that memory, which may cause problems.