How to display only the lowest value from a result set (MYSQL)

Question

I have the following statement:

select DATE(recieved_on) as Day, round (count(*) / 24)  AS 'average'
from message
where facility in ('FACID')
AND received on BETWEEN '2022-05-29 00:00:00' AND '2022-06-04 23:59:59'
GROUP BY DATE(received on);

It provides the following result set:

day	average
date	value
date	value
date	value
date	value
date	value
date	value
date	value

How to display only the lowest value in the result set instead of all 7 values?

Answer 1

You just need to use order by and limit:

select DATE(recieved_on) as Day, round (count(*) / 24) AS 'average'
from message
where facility in ('FACID') AND received on BETWEEN '2022-05-29 00:00:00' AND '2022-06-04 23:59:59'
GROUP BY DATE(received on)
order by average
limit 1