I'm trying to use echo
in this code<?php require 'connect.php'; $query = mysqli_query($conn, "SELECT * FROM `videos`") or die(mysqli_error()); while($fetch = mysqli_fetch_array($query)){ $id= $fetch['id']; ?> <?php echo " <li class='col-lg-4 col-md-6 col-dm-12'> <div class='da-card box-shadow'> <div class='da-card-photo'> <img src=' echo $fetch['video_name']' alt=''> <div class='da-overlay'> <div class='da-social'> <h4 class='mb-10 color-white pd-20'></h4> <ul class='clearfix'> <li> <a href='' data-fancybox='images'><i class='fa fa-picture-o'></i></a> </li> <li> <a href='#'><i class='fa fa-link'></i></a> </li> </ul> </div> </div> </div> </div> </li> "; ?> <?php } ?>
I get this errorParse Error: Syntax error, unexpected string content "", expecting "-" or identifier or variable or number at line C:\xampp\htdocs\desk\gallery.php 572
Why does this error occur?
................................................................. ....…………
P粉3489155722024-04-05 09:23:10
You can escape the string and concatenate the variable where you want it, like this:
"; ?>