Component as a property with omitted parameters

Question

I want to define a property that must be a component with an omitted property.

I have a validation component with some properties:

interface ValidationProps {
    value: string,
    check: Array<(value) => boolean>
}

const Validation: FC<ValidationProps> = function(){}
export default Validation;

I have an input component.

interface InputProps {
    value: string,
    onChange: (e: SyntaticEvent) => void,
    validations: ???
}

const Input: FC<InputProps> = function(props){
    return <span>
        <input value={props.value} onChange={props.onChange} />
        {React.cloneElement(props.validations, {value})}
    </span>
}
export default Input;

So I want to define InputProps.validations must be a Validation but omit the value prop.

should be used like this:

<Input value="value" onChange={...} validations={<Validation check={[(value) => value != null, (value) => value.length <= 5]} />} />

Answer 1

I'm not completely clear on what you want to achieve here, so I'm probably missing something...

But you cannot directly specify that prop must be a component with specific properties. You can , but specify validations: omit <ValidationProps, 'value'/> and substitute {React.cloneElement(props.validations, {value})} Just instantiate your <validation check={props.validations} value={value}/>

in the input

renew:

If you don't want a dependency between two components (input and validation), there can't be a dependency between the props interfaces either, unless you share them in a third module imported by both.

In this case, you can abstract further and make the validations a render prop, like validations: (value) => ReactElement. It can then be used as before, but with the added "thick arrow" syntax

  value != null, (value) => value.length <= 5]} />} />

Just call validations(value) to instantiate instead of cloneElement.

This does abstract it to the point of too much flexibility, since anything can be injected into the validation render props.