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Find a value in a multidimensional array and return the value in the same array

I'm trying to find a value in an array of milti arrays and after finding it I want to return a different key, not sure how to explain further.

I have an array:

tempArray( [0] => Array
    (
        [id] => 18460
        [field_id] => 14
        [parent_id] => 165
        [custom_tab_field_id] => 17775
        [status] => 0
        [field_type] => 0
    )

[1] => Array
    (
        [id] => 18461
        [field_id] => 2
        [parent_id] => 165
        [custom_tab_field_id] => 17776
        [status] => 0
        [field_type] => 2
    )

[2] => Array
    (
        [id] => 18462
        [field_id] => 12
        [parent_id] => 165
        [custom_tab_field_id] => 17777
        [status] => 2
        [field_type] => 2
    ))

I'm trying to find an array by [custom_tab_field_id] and return the current array [status].

I created a function that is supposed to do this, but it always returns 0.

Function:

function searchForStatus($id, $array){
        
        $returnedStatus = "0";
        foreach ($array as $key => $val){
            if ($val['custom_tab_field_id'] == $id){
                return $returnedStatus = $array[$key]['status'];
            }
        }
        return $returnedStatus;
    }

Then just call the function by passing the value

$returnedStatus = searchForStatus($field['custom_tab_field_id'], $tempArr);

P粉958986070P粉958986070222 days ago452

reply all(2)I'll reply

  • P粉416996828

    P粉4169968282024-04-04 10:24:16

    Can be solved using the array-filter function. Right now

    $a1 = [
        ['id' => 1, 'status', 'active'], 
        ['id' => 2, 'status', 'in-active']
    ];
    
    $search = 2;
    
    print_r(array_filter($a1, function ($object) use ($search) {
        return $object['id'] == $search;
    }));

    It will return the entire array from the array matching the search id.

    You can also write a function for this

    function search($data, $searchValue, $searchField, $returnField) {
    
        $filter = array_filter($data, function ($object) use ($searchValue, $searchField) {
          return $object[$searchField] == $searchValue;
        });
    
       return count($filter) > 0 ? $filter[0][$returnField] : null;
    
    }

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    0
  • P粉921130067

    P粉9211300672024-04-04 09:24:48

    Using the array_column function, this can be easily solved and is very general.

    $array = [
      ['id' => 18460, 'field_id' => 14, 'parent_id' => 165, 'custom_tab_field_id' => 17775, 'status' => 0, 'field_type' => 0],
      ['id' => 18460, 'field_id' => 2, 'parent_id' => 165, 'custom_tab_field_id' => 17776, 'status' => 0, 'field_type' => 2],
      ['id' => 18460, 'field_id' => 14, 'parent_id' => 165, 'custom_tab_field_id' => 17777, 'status' => 2, 'field_type' => 2],
    ];
    
    $findKey = 'custom_tab_field_id';
    $getKey = 'status';
    $findVal = 17777;
    
    $arrKeyValue = array_column($array,$getKey,$findKey);
    
    $status = $arrKeyValue[$findVal];  //2

    This solution does not include error handling, it only shows the principle. $arrKeyValue is an array, how to:

    array (
      17775 => 0,
      17776 => 0,
      17777 => 2,
    )

    Try it yourselfhttps://3v4l.org/SnVM4

    reply
    0
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