I want to shuffle an array of elements in JavaScript like this:
[0, 3, 3] -> [3, 0, 3] [9, 3, 6, 0, 6] -> [0, 3, 6, 9, 6] [3, 3, 6, 0, 6] -> [0, 3, 6, 3, 6]
P粉5904283572023-10-12 16:14:29
You can use Fisher-Yates Shuffle (code adapted from this website):
function shuffle(array) { let counter = array.length; // While there are elements in the array while (counter > 0) { // Pick a random index let index = Math.floor(Math.random() * counter); // Decrease counter by 1 counter--; // And swap the last element with it let temp = array[counter]; array[counter] = array[index]; array[index] = temp; } return array; }
P粉3161107792023-10-12 10:21:15
Uses a modern version of the Fisher–Yates shuffling algorithm :
/** * Shuffles array in place. * @param {Array} a items An array containing the items. */ function shuffle(a) { var j, x, i; for (i = a.length - 1; i > 0; i--) { j = Math.floor(Math.random() * (i + 1)); x = a[i]; a[i] = a[j]; a[j] = x; } return a; }
/** * Shuffles array in place. ES6 version * @param {Array} a items An array containing the items. */ function shuffle(a) { for (let i = a.length - 1; i > 0; i--) { const j = Math.floor(Math.random() * (i + 1)); [a[i], a[j]] = [a[j], a[i]]; } return a; }
But be aware that using destructuring swap variables As of October 2017, allocations can incur severe performance penalties.
var myArray = ['1','2','3','4','5','6','7','8','9']; shuffle(myArray);
Using Object.defineProperty
(Method taken from this SO answer) we can also implement the function as a prototype method for the array without having to have it appear in something like in a loop like for (i in arr)
. The following code will allow you to call arr.shuffle()
to shuffle an array arr
:
Object.defineProperty(Array.prototype, 'shuffle', { value: function() { for (let i = this.length - 1; i > 0; i--) { const j = Math.floor(Math.random() * (i + 1)); [this[i], this[j]] = [this[j], this[i]]; } return this; } });