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function through chain method

Trying to understand chained methods, either like math or cheerio/jQuery, when things get too long I shorten and replace with my own methods.

//这将帮助我在复杂的方法中获得缩短的方法,并应用于项目

function getValue() {  
    this.add = function(y) {
        return x + y;
    };

    this.mult = function(y) {
        return x * y;
    };

    return this;
};

//不使用new操作符的实例会很有趣

const price1 = getValue(8);
const price2 = getValue(2).add(1);
const price3 = getValue(5).add(3).mult(2);

//不重要,但是推进更远:
const price4 = getValue().add(2).add(2);
const price5 = getValue(5).add(2).add(2);

console.log(price1); // 期望值为8
console.log(price2); // 期望值为3
console.log(price3); // 期望值为16
console.log(price4); // 期望值为4
console.log(price5); // 期望值为9
P粉916553895P粉916553895452 days ago616

reply all(2)I'll reply

  • P粉884548619

    P粉8845486192023-09-07 19:35:42

    I improved the above code by adding a default value for y to prevent the result from being "nan" when y is not provided. Overall, this is a great answer.

    function getValue(x = 0) {
      this.x = x;
      this.add = function(y = 0) {
        this.x += y;
        return this;
      };
      this.mult = function(y = 1) {
        this.x *= y;
        return this;
      };
      this.value = function() {
        return this.x;
      };
      return this;
    };
    
    const price1 = getValue(8).value();
    const price2 = getValue(2).add(1).value();
    const price3 = getValue(5).add(3).mult(2).value();
    const price4 = getValue().add(2).add(2).value();
    const price5 = getValue(5).add(2).add(2).value();
    
    console.log(price1); // 期望输出 8
    console.log(price2); // 期望输出 3
    console.log(price3); // 期望输出 16
    console.log(price4); // 期望输出 4
    console.log(price5); // 期望输出 9

    reply
    0
  • P粉739079318

    P粉7390793182023-09-07 12:11:26

    You need to use the getValue function to receive a parameter x. Additionally, your chained functions should return this. Finally, you need a function to unpack the value, i.e. value().

    Please note that in price4, you do not pass in the initial value, so it can default to 0.

    function getValue(x = 0) {
      this.x = x;
      this.add = function(y) {
        this.x += y;
        return this;
      };
      this.mult = function(y) {
        this.x *= y;
        return this;
      };
      this.value = function() {
        return this.x;
      };
      return this;
    };
    
    const price1 = getValue(8).value();
    const price2 = getValue(2).add(1).value();
    const price3 = getValue(5).add(3).mult(2).value();
    const price4 = getValue().add(2).add(2).value();
    const price5 = getValue(5).add(2).add(2).value();
    
    console.log(price1); // 期望值为 8
    console.log(price2); // 期望值为 3
    console.log(price3); // 期望值为 16
    console.log(price4); // 期望值为 4
    console.log(price5); // 期望值为 9

    reply
    0
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