P粉0418819242023-08-30 10:51:59
I just found another answer online一> in the comments:
Make sure your columns are well indexed and the indexes are used for filtering and sorting. Validate with explain plan.
select count(*) from table --find the number of rows
Calculate the "median" row number. Maybe use: median_row = Floor(count / 2)
.
Then select it from the list:
select val from table order by val asc limit median_row,1
This should return a row with the values you want.
P粉0417587002023-08-30 10:24:09
In MariaDB/MySQL:
SELECT AVG(dd.val) as median_val FROM ( SELECT d.val, @rownum:=@rownum+1 as `row_number`, @total_rows:=@rownum FROM data d, (SELECT @rownum:=0) r WHERE d.val is NOT NULL -- put some where clause here ORDER BY d.val ) as dd WHERE dd.row_number IN ( FLOOR((@total_rows+1)/2), FLOOR((@total_rows+2)/2) );
Steve Cohen pointed out that after the first pass, @rownum will contain the total number of rows. This can be used to determine the median, so no second pass or concatenation is required.
Additionally, AVG(dd.val)
and dd.row_number IN(...)
are used to correctly generate the median when there is an even number of records. reasoning:
SELECT FLOOR((3+1)/2),FLOOR((3+2)/2); -- when total_rows is 3, avg rows 2 and 2 SELECT FLOOR((4+1)/2),FLOOR((4+2)/2); -- when total_rows is 4, avg rows 2 and 3
Finally, MariaDB 10.3.3 includes MEDIAN functions