P粉9249157872023-08-29 11:21:21
Moved the number range
into its own CTE to separate things, we now have a large list of 80 numbers (probably larger).
Then we find the number of months between start/end and concatenate the same number of rows. Then do the math to convert the range into a selection:
WITH range_of_numbers AS ( SELECT row_number() OVER (ORDER BY SEQ4())-1 AS rn FROM TABLE(GENERATOR(rowcount=>80)) ) SELECT t1.name, t1.int_value, t1.start, t1.end, DATEADD(MONTH, r.rn, t1.start) as interval FROM table1 AS t1 JOIN range_of_numbers as r ON date_diff('month', t1.START, t1.end) <= between r.rn ORDER BY 2,1,3;
Another option is to build a long range date table
CREATE TABLE dates AS SELECT DATEADD(MONTH, row_number() OVER (ORDER BY SEQ4())-1, '1980-01-01') as month_date FROM TABLE(GENERATOR(rowcount=>8000))
Then we use BETWEEN to get the included values in the (start, end) range, which becomes:
FROM table1 AS t1 JOIN dates as d ON d.month_date BETWEEN t1.START AND t1.end
P粉5671123912023-08-29 00:50:09
WITH RECURSIVE cte AS ( SELECT name, int_value, start, `end`, 1 rownum, DATE_FORMAT(start, '%m-%Y') `interval` FROM source_table UNION ALL SELECT name, int_value, start, `end`, 1 + rownum, DATE_FORMAT(start + INTERVAL rownum MONTH, '%m-%Y') FROM cte WHERE start + INTERVAL rownum - 1 MONTH < `end` ) SELECT name, int_value, start, `end`, `interval` FROM cte ORDER BY rownum;
https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=bdd028a7755fdcb8296df2301baeb295
If you don't want the month to have leading zeros, use the '%c-%Y'
pattern.