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What does the symbol "ampersand (&)" in TypeScript type definitions mean?

<p>In line 60359 of this type definition file, there is the following statement: </p> <pre class="brush:php;toolbar:false;">type ActivatedEventHandler = ( ev: Windows.ApplicationModel.Activation.IActivatedEventArgs & WinRTEvent<any> ) => void;</pre> <p>In this context, what does the <code>&</code> symbol mean? </p>
P粉668804228P粉668804228458 days ago413

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  • P粉578343994

    P粉5783439942023-08-23 09:47:27

    Intersection types in Typescript

    • A & represents an intersection type in a type context in TS.
    • It merges all properties of two object types together and creates a new type.

    example:

    type dog = {age: number, woof: Function};
    type cat = {age: number, meow: Function};
    
    // 类型weird是cat和dog的交集
    // 它需要具有它们的所有属性的组合
    type weird = dog & cat;
    
    const weirdAnimal: weird = {age: 2, woof: () => {'woof'}, meow: () => {'meow'}}
    
    interface extaprop {
        color: string
    }
    
    type catDog = weird & extaprop; // 类型现在还添加了color属性
    const weirdAnimal2: catDog = {age: 2, woof: () => {'woof'}, meow: () => {'meow'}, color: 'red'}
    
    
    // 这与联合类型不同
    // 下面的类型表示猫或狗
    type dogOrCat = dog | cat;

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  • P粉148434742

    P粉1484347422023-08-23 00:44:51

    & represents the intersection type in the type position.

    More TypeScript documentation on intersection types:

    https://www.typescriptlang.org/docs/handbook/2/objects.html#intersection-types

    Quoted from the above document:

    interface ErrorHandling {
      success: boolean;
      error?: { message: string };
    }
    
    interface ArtworksData {
      artworks: { title: string }[];
    }
    
    interface ArtistsData {
      artists: { name: string }[];
    }
    
    // 这些接口被组合在一起,以具有
    // 一致的错误处理和它们自己的数据。
    
    type ArtworksResponse = ArtworksData & ErrorHandling;
    type ArtistsResponse = ArtistsData & ErrorHandling;
    
    const handleArtistsResponse = (response: ArtistsResponse) => {
      if (response.error) {
        console.error(response.error.message);
        return;
      }
    
      console.log(response.artists);
    };

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