Sort an array of objects based on property values

Question

I obtained the following objects using AJAX and stored them in an array:

var homes = [
    {
        "h_id": "3",
        "city": "Dallas",
        "state": "Texas",
        "zip": "75201",
        "price": "162500"
    }, {
        "h_id": "4",
        "city": "Beverly Hills",
        "state": "California",
        "zip": "90210",
        "price": "319250"
    }, {
        "h_id": "5",
        "city": "New York",
        "state": "New York State",
        "zip": "00010",
        "price": "962500"
    }
];

How can I create a function using JavaScript that sorts objects in ascending or descending order using only the price property?

Answer 1

This is a more flexible version that allows you to create reusable sort functions and sort by any field.

const sort_by = (field, reverse, primer) => {

  const key = primer ?
    function(x) {
      return primer(x[field])
    } :
    function(x) {
      return x[field]
    };

  reverse = !reverse ? 1 : -1;

  return function(a, b) {
    return a = key(a), b = key(b), reverse * ((a > b) - (b > a));
  }
}


//现在您可以按任何字段排序...

const homes=[{h_id:"3",city:"Dallas",state:"TX",zip:"75201",price:"162500"},{h_id:"4",city:"Bevery Hills",state:"CA",zip:"90210",price:"319250"},{h_id:"5",city:"New York",state:"NY",zip:"00010",price:"962500"}];

// 按价格从高到低排序
console.log(homes.sort(sort_by('price', true, parseInt)));

// 按城市排序，不区分大小写，按A-Z排序
console.log(homes.sort(sort_by('city', false, (a) =>  a.toUpperCase()
)));

Answer 2

Sort homes by price in ascending order:

homes.sort(function(a, b) {
    return parseFloat(a.price) - parseFloat(b.price);
});

Or after ES6 version:

homes.sort((a, b) => parseFloat(a.price) - parseFloat(b.price));

Some documentation can be found here.

To sort in descending order you can use

homes.sort((a, b) => parseFloat(b.price) - parseFloat(a.price));