P粉7446912052023-07-26 10:58:55
You will need to use a subquery to achieve this. Actually, you need to get the maximum recorded version for each appointment ID:
SELECT appointment_record_version_number, appointment_id, appointment_pallets AS close_pallets, appointment_units AS close_units FROM b.dh AS t1 WHERE t1.appointment_record_version_number = ( SELECT MAX(appointment_record_version_number) FROM b.dh WHERE b.dh.data = t1.data ) AND last_updated_datetime BETWEEN '2023-06-01' AND '2023-06-30' AND warehouse_id = 'xxx'
You can also use a JOIN statement to select the maximum value, which is sometimes faster:
SELECT t1.appointment_record_version_number, t1.appointment_id, t1.appointment_pallets AS close_pallets, t1.appointment_units AS close_units FROM b.dh AS t1 LEFT JOIN b.dh AS t2 ON ( t1.appointment_record_version_number = t2.appointment_record_version_number AND t1.appointment_id < t2.appointment_id ) WHERE t2.appointment_record_version_number IS NULL AND last_updated_datetime BETWEEN '2023-06-01' AND '2023-06-30' AND warehouse_id = 'xxx';
Depending on your use case, especially if your database is large, you can use additional subqueries or indexes to further optimize the request, but it's already pretty fast.