Default parameter problem

Question

Teacher, in the example you gave:

function func2(param1, param2) {

param1 = arguments[0] ? param1 : 600;

param2 = arguments[1] ? param1 : 300;

}

This ternary operator, if I call it like this: func(0, 0,);

I pass in If the parameter is 0, it will actually be judged as failure, and param1 and param2 will be assigned values ​​of 600 and 300

Answer 1

It is inappropriate to set default parameter values ​​in this way. In fact, js now supports default parameters, so there is no need for such trouble (es6)