Could you please tell me how to call the following heartbeat monitoring code? Thanks!

Question

The following is the heartbeat monitoring code snippet of the web server background that keeps it running at all times through the "php XXX.php" command. How do I display $A in try on the front-end browser? Thanks!

while (true) {

if ($stomp == null || !$stomp->getClient()->isConnected()) {

echo "connection not exists, will reconnect after 10s.", PHP_EOL;

sleep(10);

$stomp = start_consume();

}

## Try {

Business logic.

$A = $stomp->read();

echo "start consumer:";

echo "<br/>";

// echo $A;

$arr = explode(':',$A);

// echo "<br/>";

// $B = json_decode($A,true);

$arr1 = ($arr[16]);

// var_dump ($arr1[0]);

echo "<br/>";

$B = json_encode($arr1,true);

echo $B;

// $B1 = json_decode($B,true);

echo "<br/>";

}

catch(HeartbeatException $e) {

echo 'The server failed to send us heartbeats within the defined interval.', PHP_EOL;

$stomp->getClient()->disconnect();

} catch (Exception $e) {

echo 'process message occurs error '. $e->getMessage() , PHP_EOL;

}

Answer 1

Yours is PHP code, heartbeat monitoring. You use the front-end to always request this method. When $A is passed to the front-end, you pass it how you pass the value to the front-end.

Generally, the front end uses ajax to request php, and php uses echo json_encode to return to ajax