php数组转换的问题

Question

Array(
[server] => Array(
        [0] => hk
        [1] => jp
    )
[fromdate] => Array(
        [0] => 2013-07-17
        [1] => 2013-06-19
))

以上数组如果最快最简单的方法转换成为

Array(
[0] => Array(
    [server] => 'hk',
    [fromdate] => '2013-07-17'
)
[1] => Array(
    [server] => 'jp',
    [fromdate] => '2013-07-17'
))

Answer 1

// 源数组
$source = array(
    'server' => array('hk','jp'),
    'fromdate' => array('2013-07-17','2013-07-08')
);

//目标数组
$result = array();
foreach($source as $key=>$value){
    $j = 0;
    // 当然用这里用foreach也可以实现,但是for循环更能直观了解它的怎么工作的。
    for($i=0;$i<count($value);$i++){
        $result[$j][$key] = $value[$i];
        $j++;
    }
    /* foreach实现
    foreach($value as $val){
        $result[$j][$key] = $val;
        $j++;
    }
    */
}

// 输出结果
echo '<pre>';
print_r($result);
echo '</pre>';

Answer 2

$source = array(
    'server' => array('hk','jp'),
    'fromdate' => array('2013-07-17','2013-07-08')
);
$new_array = array_map(function($server,$fromdate) {
    return array('server'=>$server,'fromdate'=>$fromdate);
}, $source['server'],$source['fromdate']); //代码比较少