javascript - Problems encountered with Lazyload

Question

When lazyload is used in this way, only the last container is valid, but the above two containers are invalid?
Could you guys please give me the same answer? ! Thanks.

This is the setting of lazyload. Use each to loop out each container ".lazy".

This is how to write the p of each container. The third one is written the same way.

Answer 1

Wow, you actually wrote it like this, it’s going to explode.

Just use ("img.lazy") directly