I put
data () {
return {
isActive: 'a'
}
}, If the 'a' in
is replaced with 'b', the published words will change color
<template lang="html">
<p class="footer">
<p class="footer-box">
<router-link :class="{'active': isActive === 'a'}" @click="select('a')" to="/" class="item">首页</router-link>
<router-link :class="{'active': isActive === 'b'}" @click="select('b')" to="/create" class="item">发表</router-link>
<router-link :class="{'active': isActive === 'c'}" @click="select('c')" to="/message" class="item">消息</router-link>
<router-link :class="{'active': isActive === 'd'}" @click="select('d')" to="/user" class="item">我的</router-link>
</p>
</p>
</template>
<script>
export default {
data () {
return {
isActive: 'a'
}
},
methods: {
select (value) {
this.isActive = value
}
}
}
</script>
<style lang="less">
.footer {
position: fixed;
left: 0;
bottom: 0;
height: 50px;
width: 100%;
background-color: #fff;
border-top: 1px solid #bbb;
.footer-box {
display: flex;
height: 50px;
width: 100%;
line-height: 40px;
.item {
flex: 1;
text-align: center;
}
}
}
.active {
color: #41B883;
}
</style>
曾经蜡笔没有小新2017-07-05 10:42:18
What you wrote is too complicated. This can be done by writing a linkActiveClass when configuring the route. It is recommended to read the documentation of vue-router.
The configuration can be written in the main.js defined route.
const router = new VueRouter({
linkActiveClass: "active", //设置点击状态的class
mode: 'hash',
hashbang:true,
routes:routerConfig
})
Then add the .active{color: #41B883;} style to your .vue style
router-link is written like this<router-link to="/" class="item">Homepage</router-link>
習慣沉默2017-07-05 10:42:18
It should be enough to replace it with @click.native. Of course, the method above is better
阿神2017-07-05 10:42:18
Replace the click event with @click.native="select('a')";
When writing this kind of navigation, I usually use this method, v-for
<ul>
<li v-for="(item,index) in liData" :class=" {active:$route.matched[0].path==item.label}" ><router-link :to="item.label">{{item.name}}</router-link></li>
</ul>
data(){
return {
liData:[
{name:"首页",label:"/home"},
{name:"设计器",label:"/designer"},
{name:"任务管理",label:"/taskmanger"},
{name:"节点管理",label:"/node"}
]
},
这里的active的变化就是根据地址栏中变化而变化,这样前进后退都不会有问题
过去多啦不再A梦2017-07-05 10:42:18
<router-link :to="item.url" active-class="act-bar" tag="li" exact>
</router-link>
You can define the selected style .act-bar{}
淡淡烟草味2017-07-05 10:42:18
<p class="footer-box">
<router-link to="/">
首页
</router-link>
</p>
.router-link-active{
color: #41B883;
}
Just do this. The color set in .router-link-active is the router-link you are currently clicking on. The style color after activation can also be set to other styles, and then other router-links will be restored to the default. Style