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As shown in the figure, only the content of cout can be displayed in the input box. The variables that need to be entered in cin cannot be input. The input box cannot be typed at all. Is there any solution or alternative?
PHP中文网2017-07-03 11:43:56
给我你的怀抱2017-07-03 11:43:56
Click the terminal tab, or ctrl + ~ to open it directly
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