javascript - An assignment operation problem

Question

var a=0;
b=(a=3) (a=4);
alert(a);
alert(b);
Result a=4,b= 7

I would like to ask, why is a 4? Is the assignment operation from right to left?

Answer 1

Order of operations:

var a = 0; // a 0
b = (a = 3) + (a = 4);
// a = 3 ----> a为3，整个赋值语句返回3
// a = 4 ----> a为4，整个赋值语句返回4
// 由于返回值的内存和赋值操作用到的a的内存不同，所以b的运算所用的值，只和返回值有关，不受a的值变化的影响，因此，b = 3 + 4 = 7
// 所以，最终a为4，b为7

Answer 2

Assignment operations are combined from right to left. So the first thing is to assign (a=3)+(a=4) to b. However, (a=3)+(a=4) is executed from left to right. So it shows that 3 is assigned to a, and then 4 is assigned to a. So a ends up being 4 and b ends up being 7.

Answer 3

First execute a=3, then execute a=4, so in the end a is 4

Answer 4

a is assigned the value 4

Answer 5

b=(a=3)+(a=4) This line of code is executed from left to right. When a=3 is executed, 3 is assigned to a. When a=4, 4 is assigned to a. The final value of a is 4.