for example
aModel = {
user_id: String,
file_name: String,
page_id: Number
}
fileSchema = new Schema({
page_id: Number,
key: String,
doc: String,
title: String,
sym: String
});
bModel = {
user_id: String,
file_name: String,
origin_file: String,
new_file: [fileSchema]
}
It is known that user_id, file_name, page_id and model are asynchronous. How to search these two models at the same time?
Go to the next step after getting two results
我想大声告诉你2017-06-20 10:07:55
The code is as follows. In fact, I feel that the writing is not elegant at all...
var aDocs ,bDocs =null ;
aModel.find({ user_id:xx , file_name:xx , page_id:xx})
.then(function(docs){
aDocs = docs;
return bModel.find({ user_id:xx , file_name:xx , page_id:xx}) })
.then(function(docs){
bDocs = docs ;
other codes
})
女神的闺蜜爱上我2017-06-20 10:07:55
If you need them to execute concurrently, you can use Promise
const query1 = aModel.find(query)
const query2 = bModel.find(query)
Promise.all([query1, query2]).then(rs => {})
If you don’t need to do it concurrently and can do it synchronously, you can use yield
or async/await
const query1 = yield aModel.find(query)
const query2 = yield bModel.find(query)
// 需要node7以上
const query1 = await aModel.find(query)
const query2 = await bModel.find(query)
女神的闺蜜爱上我2017-06-20 10:07:55
Of course the upstairs is not very elegant. What you need is async/await, so upgrade node to 7.6 or above
世界只因有你2017-06-20 10:07:55
Really? Doesn't the mongoose api have a method for multi-table query?