How to compare the sizes of certain members of multiple objects in Python?

Question

There are multiple objects of the same type, a b c
Each object has the same integer attribute a.click

Now we need to sort according to the numerical value of click (there may be duplicates),

Then take out the other member data in the object according to the sorting position of click

I have been thinking about it for a long time, how to implement it

Answer 1

Is this so?

# coding: utf8

class A():
    def __init__(self):
        self.click = 0


a = A()
a.click = 4
a.test = 'I am a'

b = A()
b.click = 1
b.test = 'I am b'

c = A()
c.click = 2
c.test = 'I am c'

for i in sorted([a, b, c], key=lambda x: x.click, reverse=True):
    print i.test
    
# 输出(根据click的值从小到大输出test属性)
I am b
I am c
I am a

Answer 2

Write an example:

#!/usr/bin/python3


class Class:

    def __init__(self, key, value):
        self.key, self.value = key, value


def get_values(*args):
    return [o.value for o in sorted(args, key=lambda o: o.key)]


print(
    get_values(
        Class(3, 1),
        Class(1, 2),
        Class(2, 3)
    )
)

# Output: [2, 3, 1]

Is this what you mean