python writes the xth column data to the xth file

Question

The Python crawler needs to crawl a total of 65 pages of data, and the number of columns in each page of data is uncertain. Now I can capture the data of each column, but because the number of columns is uncertain, the file name written cannot be determined. The problem is how to write the x-th column data into the x-th file. That is, how to dynamically select the file name of file=. code show as below:

f_1 = open('fitment/1.txt', 'a')
f_2 = open('fitment/2.txt', 'a')
f_3 = open('fitment/3.txt', 'a')
for i in range(66):
    pr = random.choice(proxy)
    url = 'https://*****' + str(i) + '****'
    page_url = requests.get(url, headers=head, proxies=pr)
    page_get = page_url.text
    page_text = BeautifulSoup(page_get, 'lxml')
    fitment_1 = page_text.find_all('tr', {'class': 'fitment listRowEven'})
    for each_tag_1 in fitment_1:
        td_text_1 = each_tag_1.find_all('td')
        for x in range(len(td_text_1)+1):
            print(td_text_1[x].string, file=)

The structure of the web page is as follows, each tr tag is a column, and the specific data to be captured is located in each td tag

    <tr>
    <td>...</td>
    <td>...</td>
    <td>...</td>
    <td>...</td>
</tr>

<tr>
    <td>...</td>
    <td>...</td>
    <td>...</td>
    <td>...</td>
</tr>

Answer 1

Don’t define the open file object first, you can open the corresponding file operation based on the number of columns

with open('列数.txt', 'a') as f:
    f.write('内容')