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$a = false;$b = $a++;echo $b;结果是什么?》
曾经蜡笔没有小新2017-06-12 09:23:36
false, no invisible transformation will be done.
false
Moreover, if you write it like this, even if $a is a number. $b will not get self-increment either. Because it will increase automatically after assignment.
$a
$b