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c++ - Beginner to learn data structure, I have a small problem

Linked storage of linear tables, the following code

typedef struct Node{
    ElemType e;
    struct Node *next; 
}Node,*LinkList;

What is the difference between LinkList p and Node p

ringa_leeringa_lee2713 days ago907

reply all(2)I'll reply

  • ringa_lee

    ringa_lee2017-06-10 09:50:45

    LinkList is a pointer type, Node is a structure type.
    LinkList Pointer type variables can be used with (*p).e or p->e,Node type variables You can use p.e.

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  • 仅有的幸福

    仅有的幸福2017-06-10 09:50:45

    Ifyou understand the difference between int a and int *a, and then understand typedef int ElemType, you can understand the above example.

    typedef struct Node{
        ElemType e;
        struct Node *next; 
    } Node, *LinkList;

    First of all, from the outside, typedef [] *** is to redefine the type in [] to be represented by ***;
    in the example, it means that the intermediate structure type The variable struct Node{***} can be represented here by Node and *LinkList. Moreover,
    When you need to declare a Node variable, you can use Node p to declare it; it is equivalent to struct Node p
    When you need to declare a Node pointer variable, you can use LinkList p to declare; equivalent to struct Node *p

    Look at the structure definition in the middle:
    defines a structure type with the alias Node:
    This structure consists of a ElemType type variable e and a current structure type pointer *next
    Then every variable of this structure type you declare contains these two elements.

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