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java - I encountered an ajax problem. I executed a background method through the ajax method. (There is a value in the background, or a JSON type.) It seems that the object type is obtained in the foreground.

Through the ajax method, JSON data is returned after amateur logic processing in the background. What is obtained in the foreground is the Object type. I would like to ask what is going on.

ajax method:

$.ajax({
type:"post",
url:"user/ReturUser",
dataType:"json",
data:{"id":city},
success:function(data){
alert(data); //The output is Object:Object
});

Backstage:

@ResponseBody
@RequestMapping("/ReturUser")
public Object ReturUser(Model model){
    userss=(Users)request.getSession().getAttribute("users");
    System.out.println(JSON.toJSONString(userss)); //有值有输出
    return JSON.toJSONString(userss);
}

My ability is limited, find someone to help solve my doubts

我想大声告诉你我想大声告诉你2718 days ago1062

reply all(7)I'll reply

  • 我想大声告诉你

    我想大声告诉你2017-06-10 09:49:56

    What is returned is an object
    alert(data.balance)

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  • 女神的闺蜜爱上我

    女神的闺蜜爱上我2017-06-10 09:49:56

    JSON.stringify(data);

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    0
  • phpcn_u1582

    phpcn_u15822017-06-10 09:49:56

    Don’t alert directly, you still need to do json parsing

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    0
  • 为情所困

    为情所困2017-06-10 09:49:56

    Of course your alert will be an object_(:з ∠)_, or you can convert it into a json string and alert again to see if the data is successfully obtained

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    0
  • phpcn_u1582

    phpcn_u15822017-06-10 09:49:56

            $.ajax({
                type:"post",
                url:"user/ReturUser",
                dataType:"json",
                data:{"id":city},
                success:function(data){
                    var val = JSON.parse(data);
                    console.log(val.calls);
                }
            });

    You can just write like this in the background, and the front desk will get the User object directly

    @ResponseBody
    @RequestMapping(value="/ReturUser",method = RequestMethod.GET,produces="application/json")
    public Users ReturUser(Model model){
        userss=(Users)request.getSession().getAttribute("users");
        return userss;
    }

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    0
  • 漂亮男人

    漂亮男人2017-06-10 09:49:56

    This is correct, you can use it directly, it is recommended to use console.log(data) to print; then you need to use a specific field to directly use data.calls to get Ms. Chen

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    0
  • 女神的闺蜜爱上我

    女神的闺蜜爱上我2017-06-10 09:49:56

    What was passed was an object.
    You can debug using F12 of the browser, and then hit the breakpoint on that JS to see the value inside.

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    0
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