The following sql execution is too slow, how should it be optimized?
UPDATE AA A
SET COL1 =
(SELECT B.COL2
FROM BB B
WHERE B.BH = A.BH
AND B.YEAR = '2016-2017'
)
WHERE A.YEAR = '2017-2018';
Among them, the AA table and the BB table are the same and are one table
漂亮男人2017-06-05 11:11:33
I didn’t quite understand it,
Since it’s the same step, just
update the table set column 1 = column 2 where condition
and that’s it
習慣沉默2017-06-05 11:11:33
Create a new table based on the new value, then merge the two tables, and finally delete the temporary table;
Create a transaction, write all updates into it, and finally commit;
某草草2017-06-05 11:11:33
What I don’t understand is whether AA and BB are one table or two tables.
If it is one table, @prolifes’ method can be used.
If it is two tables,
update AA a, BB b set a.col1 = b. col2 where a.bh = b.bh and a.year='2017-2018' and b.year='2016-2017',
Also, the slowness is related to the size of your data and the index, I just give A general method, how effective it is, you have to try it yourself
ringa_lee2017-06-05 11:11:33
Thank you for your suggestions. In the end, I used the one on the Internet, which is slightly more efficient:
Oracle has two methods:
Inline view update
update (
select t1.id t1id ,t1.nickname t1nickname,t1.playNum t1playnum,t2.id t2id ,t2.nickname t2nickname,t2.playNum t2playnum
from t1 inner join t2 on (t1.id=t2.id)
)
set t1nickname=t2nickname,t1playnum=t2playnum;