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mysql - How to implement this query with a sql

Query the number of different statuses grouped by user_id (that is, the same status 1) for each user when the exam_publish_id is (1, 2, 3).
The table structure is as follows:

Expect the following results:

user_id status1 status2 status3
27047     2       1         0
27410     0       2         1
27047     1       1         1
ringa_leeringa_lee2793 days ago546

reply all(1)I'll reply

  • 怪我咯

    怪我咯2017-05-24 11:34:47

    Finally tried it out. . . The answer is as follows:

    SELECT user_id, COUNT(IF(status=0,true, null)) AS 'right_count', COUNT(IF(status=1,true, null)) AS 'error_count', COUNT(IF(status=2,true, null)) AS 'absenteeism_count' FROM online_exam_user_detail WHERE exam_publish_id in (1, 2, 3) GROUP BY user_id;
    

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