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javascript - How to display images obtained in the background on the page

success:function(data){

                issueType = data.issueType;    
                console.log(data.lstFile);
                aba.innerHTML = "";                    
                var fileName;
                var len = data.lstFile.length;

// document.getElementById("imgSrc").src = baseServerUrl fileUrl;

                for(var i = 0; i < len; i++){
                    var li = document.createElement("li");
                    var fileUrl = data.lstFile[i].fileUrl;
                    li.className = "mui-table-view-cell mui-table";
                    li.innerHTML = "<label>附件内容:</label>"+"<span>"+data.lstFile[i].fileName+"</span>"+"<img id='imgSrc' src=''>";
                    aba.appendChild(li);

// console.log(data.lstFile.length);
// console.log($("#imgSrc").attr("src"));

                    $("#img").attr("src","http://218.17.104.170:8082/upload/attachment/20170412070145109.jpg");`![请输入代码][1]`

Please give me some advice, I have been troubled for a few days

PHP中文网PHP中文网2816 days ago432

reply all(1)I'll reply

  • 淡淡烟草味

    淡淡烟草味2017-05-19 10:44:11

    The id is wrong, it should be $("#imgSrc").attr("src","http://218.17.104.170:8082/upload/attachment/20170412070145109.jpg");

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