//给数组中的每一项增加3
function addThreeForEachItem(array){
for(var i = 0; i < array.length; i++){
array[i] = array[i] + 3;
}
return array;
}
//将数组中的每一项编码
function encodeEachItem(array){
for(var i = 0; i < array.length; i++){
array[i] = encodeURIComponent(array[i]);
}
return array;
}
The two functions are very similar (duplicate). How to encapsulate the repeated parts of these two functions into one function?
某草草2017-05-19 10:11:46
There is a native method without encapsulation
array.map(item=>item+3)
array.map(item=>encodeURIComponent(item))
巴扎黑2017-05-19 10:11:46
可以考虑给第二个参数来区分
function repeatControl(array,param){
for(var i = 0; i < array.length; i++){
if(param=='addThree'){
array[i] + = 3;
}else{
array[i] = encodeURIComponent(array[i]);
}
}
return array;
}