How to convert string to list in python

Question

How to convert a string such as a = "I am Chinese" into a list li =["I","是","中","国","人"]

a = "我是一个中国人"
li = list(a)
print li

The output is

['\xe6', '\x88', '\x91', '\xe6', '\x98', '\xaf', '\xe4', '\xb8', '\x80', '\xe4', '\xb8', '\xaa', '\xe4', '\xb8', '\xad', '\xe5', '\x9b', '\xbd', '\xe4', '\xba', '\xba']

I implemented it very simply using JavaScript

var a = "我是中国人"
li = a.split("")
console.log(li) // >>>["我","是","中","国","人"]

Don’t know how to implement it in python?

Answer 1

You can first decode the string into unicode, 再用list

# 第一种:
>>> a = u"我是中国人"
>>> s = list(a)
>>> print s
[u'\u6211', u'\u662f', u'\u4e2d', u'\u56fd', u'\u4eba']
>>> print s[1]
是

# 第二种
>>> a = "我是中国人"
>>> s = a.decode('utf8')
>>> s = list(a.decode('utf8'))
>>> s
[u'\u6211', u'\u662f', u'\u4e2d', u'\u56fd', u'\u4eba']
>>> print s[1]
是

Answer 2

Using python3

Answer 3

python3 has no encoding issues

In [20]: a
Out[20]: '我是中国人'

In [21]: li=list(a)

In [22]: li
Out[22]: ['我', '是', '中', '国', '人']

Answer 4

# -*- coding: utf-8 -*-
def unicode_chars(s):
    if not isinstance(s, unicode):
        s = s.decode("utf-8")
    return [c for c in s]

print unicode_chars("我是中国人")[0]
print unicode_chars(u"我是中国人")[1]
print unicode_chars(r"我是中国人")[2]
print unicode_chars(b"我是中国人")[3]
#>> 我
#>> 是
#>> 中
#>> 国

Answer 5

1. No need to list(a), just

for each in a:   
    print each
      

That’s it, it has nothing to do with coding, nor does it have to do with python2 or python3

2. You can directly treat a as a list. To obtain it, just use a[num] to slice it. For example, to obtain "I", it is a[0], and to obtain "China", you can use a[2:3]