SQLiteHaving clause
The HAVING clause allows specifying conditions to filter the grouped results that will appear in the final result.
The WHERE clause sets conditions on the selected columns, while the HAVING clause sets conditions on the grouping created by the GROUP BY clause.
Syntax
The following is the position of the HAVING clause in the SELECT query:
SELECT
FROM
WHERE
GROUP BY
HAVING
ORDER BY
FROM
WHERE
GROUP BY
HAVING
ORDER BY
In a query, the HAVING clause must be placed after the GROUP BY clause and before the ORDER BY clause. The following is the syntax of a SELECT statement containing a HAVING clause:
SELECT column1, column2
FROM table1, table2
WHERE [ conditions ]
GROUP BY column1, column2
HAVING [ conditions ]
ORDER BY column1, column2
FROM table1, table2
WHERE [ conditions ]
GROUP BY column1, column2
HAVING [ conditions ]
ORDER BY column1, column2
Example
Assume that the COMPANY table has the following records:
ID ID name ------------------------------------------------------------------------------------------------—
1 Paul 32 California 20000.0
2 Allen 25 Texas 15000.0
3 Teddy 23 Norway 20000.0
4 Mark 25 Rich-Mond 65000.0
5 David 27 TEXAS 85000.0
6 Kim 22 South-Hall 45000.0
7 James 10000.0
8 P AUL 24 Houston 20000.0
9 James 44 Norway 5000.0
10 James 45 Texas 5000.0
1 Paul 32 California 20000.0
2 Allen 25 Texas 15000.0
3 Teddy 23 Norway 20000.0
4 Mark 25 Rich-Mond 65000.0
5 David 27 TEXAS 85000.0
6 Kim 22 South-Hall 45000.0
7 James 10000.0
8 P AUL 24 Houston 20000.0
9 James 44 Norway 5000.0
10 James 45 Texas 5000.0
sqlite > SELECT * FROM COMPANY GROUP BY name HAVING count(name) < 2;The following is an example. Show all records with name count greater than 2:
This will produce the following results:
ID ------ ---------- ----------
2 Allen 25 Texas 15000
5 David 27 Texas 85000
6 Kim 22 South- Hall 45000
4 Mark 25 Rich-Mond 65000
3 Teddy 23 Norway 20000
2 Allen 25 Texas 15000
5 David 27 Texas 85000
6 Kim 22 South- Hall 45000
4 Mark 25 Rich-Mond 65000
3 Teddy 23 Norway 20000
sqlite > SELECT * FROM COMPANY GROUP BY name HAVING count(name) > 2;
This will produce the following results: ID NAME AGE ADDRESS SALARY
---------- ---------- ---------- ---------- ----- -----
10 James 45 Texas 5000
10 James 45 Texas 5000