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angular.js - angularjs如何实现点击li添加class，再次点击removeclass,且不相互影响

<!DOCTYPE html>
<html ng-app="myapp">
<head lang="en">
    <meta charset="UTF-8">
    <title></title>
    <script src="angular.min.js"></script>
    <script>
    var m1 = angular.module('myapp',[]);
        m1.controller('Aaa',function($scope){
            $scope.colors = [{
                'id':'1',
                'name':'red'
            },{
                'id':'2',
                'name':'green'
            },{
                'id':'3',
                'name':'blue'
            }];
        });
    </script>
</head>
<body>
    <p ng-controller="Aaa">
        <ul>
            <li ng-repeat="color in colors">{{color.name}}</li>
        </ul>
    </p>
</body>
</html>

需要用到id对应起来吗？

世界只因有你世界只因有你2744 hari yang lalu2518

membalas semua(3)saya akan balas

  • 给我你的怀抱

    给我你的怀抱2017-05-15 16:54:53

    Ia tidak semestinya rumit seperti di atas. 

    <ul>
    <li ng-class="{red : color.active}" ng-click="color.active = !color.active" ng-repeat="color in Texture">{{color.value}}</li>
</ul>

    balas
    0
  • ringa_lee

    ringa_lee2017-05-15 16:54:53

    Subjek harus menggunakan arahan Angular untuk mencapai keperluan ini.
    Keputusan: http://output.jsbin.com/rolobakaya

    javascriptm1.directive('toggleClass', function(){
    return {
        restrict: 'A',
        scope: {
            toggleClass: '@'
        },
        link: function($scope, $element){
            $element.on('click', function(){
                $element.toggleClass($scope.toggleClass);
            });
        }
    };
});

    html<li toggle-class="classname"></li>

    balas
    0
  • 高洛峰

    高洛峰2017-05-15 16:54:53

    Idea saya ialah: 

    <li ng-class="{active: currentId == color.id}" ng-repeat="color in colors">{{color.name}}</li>

    Kemudian tentukan ng-click dan ubah suai $scope.currentId

    di dalamnya

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    0
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