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angular.js - angular怎么写出带全选反选增删单行单列的表格?

angular怎么写出带全选反选增删单行单列的表格?并且能够有一个数组是选中的项的数据,不用jq

迷茫迷茫2744 hari yang lalu586

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  • 过去多啦不再A梦

    过去多啦不再A梦2017-05-15 16:52:17

    <!DOCTYPE html>
    <html lang="ms" >

    <kepala>

    <tajuk>Dokumen</title>
    <script src="angular.js"></script>
    <script src="checklist.js"></script>
    <script src="app.js"></script>
    </head>

    <badan>

    <input type="checkbox" ng-checked="user.roles.length == roles.length" ng-click="checkAll()" >全选/反选


    <input type="checkbox" checklist-model="user.roles" checklist-value="role" > {{role.text}}



        <br>
        <br> user.roles {{ user.roles}}<br>
        <br> role.id {{ids}}<br>
        <button class="right radius reveal-button" ng-click="del()">删除</button>
    </p>
    

    </badan>

    </html>

    var app = angular.module("app", ["checklist-model"]);

    app.controller('Ctrl', function($scope) {
    $scope.roles = [
    {id: 1, teks: 'tetamu'},
    {id: 2, teks: 'pengguna'},
    {id: 3, teks: 'pelanggan'},
    {id: 4, teks: 'admin'}
    ];
    $scope.ids = [];
    //选择的结果集合
    $scope.user = {
    peranan: []
    };

    $scope.checkAll = function() {
    console.log($scope.user.roles.length == $scope.roles.length)
    if($scope.user.roles.length == $scope.roles.length){
    $scope.user.roles = [];
    $scope.ids = [];
    }lain{
    $scope.user.roles = angular.copy($scope.roles);
    $scope.ids = [];
    }

    };
    $scope.del =function(){
    untuk(x dalam $scope.user.roles){
    $scope.ids.push($scope.user.roles[x].id);
    }

    console.log($scope.ids)
    };

    });

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