Rumah > Soal Jawab > teks badan
我用了antdesign的插件,想实现从后台获取一个数据num,然后根据这个num循环n变,输出单选框<RadioButton value="c">张三</RadioButton>,但是控制台直接报错了
ps.这是jsx页面
[ERROR] parser.babel-5.x: /page/localExaminationPlan2/app/components/appointExpertPostForm.jsx: Unexpected token (125:2
2) [E:/mavenWorkspace/labsforce/FrontEnd/lcy/myProject/page/localExaminationPlan2/app/components/appointExpertPostForm.j
sx]
我该怎么写?
let formClass = React.createClass({
//注意处理提交表单,准备数据给ok action
handleSubmit(e) {
//表单校验
console.log('-----');
let validateResult = this.props.form.validateFieldsAndScroll((errors, values) => {
if (!!errors) {
console.log('Errors in form!!!');
return;
}else{
let params = ObjectAssign(//将隐藏值一并提交,如父id
this.props.appointExpertPostFormReduce.get('fieldValues').toJSON(),
this.props.form.getFieldsValue());
this.props.appointExpertPostFormAction.onOk(
params,
this.props.notificationAction,
Notification,
this.postFormCallBack);
}
});
},
//表单提交成功回调
postFormCallBack(){
this.props.declarationDetailTableComponent.queryRecords();
},
queryRecords(params={}){
//2.add order query 由table onFieldsChange 传入参数
let wheresParma = [];
let queryParam = {};
let queryFormParams = {};
queryFormParams.wheres = wheresParma;
queryParam.queryFormParams = queryFormParams;
let paramsAssign = ObjectAssign(
this.props.appointExpertPostFormReduce.get('pagination').toJSON(),
queryParam,
params);
paramsAssign.queryFormParams = JSON.stringify(paramsAssign.queryFormParams);
this.props.appointExpertPostFormAction.onShowPostForm(paramsAssign,this.props.notificationAction,Notification);
},
render() {
const {appointExpertPostFormReduce,appointExpertPostFormAction} = this.props;
const formItemLayout = {
labelCol: { span: 6 },
wrapperCol: { span: 27 },
};
return (
<p style={{display:"inline"}}>
<Modal title="指派专家"
visible={this.props.appointExpertPostFormReduce.get('addModleVisible')}
confirmLoading={this.props.appointExpertPostFormReduce.get('confirmLoading')}
width={583}
maskClosable={false}
footer={[
<Button style={{backGround:"#000"}} key="btn" type="ghost" size="large" onClick={this.props.appointExpertPostFormAction.onCancel}>
取 消
</Button>,
<Button key="submit" type="primary" size="large" onClick={this.handleSubmit}>
确 定
</Button>,
]}
>
<Form horizontal>
<p id="box">
<FormItem {...formItemLayout} label="选择专家">
<RadioGroup defaultValue="a" size="large">
<RadioButton value="a">赵六</RadioButton>
<RadioButton value="b">李四</RadioButton>
<RadioButton value="c">王五</RadioButton>
<RadioButton value="d">张三</RadioButton>
</RadioGroup>
</FormItem>
</p>
</Form>
</Modal>
</p>
);
},
});
var PostForm = Form.create()(formClass);
module.exports = PostForm;
大家讲道理2017-04-17 15:10:43
比较简单的,在render函数里面定义一个array,然后for里面生成的东西依次push进去,最后显示
render() {
let shows = []
for (let i = 0; i < this.props.appointExpertPostFormReduce.num; i++){
shows.push(<RadioButton value={/*具体value*/} key={i}>{/*具体显示*/}</RadioButton>)
}
return (
<p style={{display:"inline"}}>
//前面省略,贴代码最好省略无关的内容
<Form horizontal>
<p id="box">
<FormItem {...formItemLayout} label="选择专家">
<RadioGroup defaultValue="a" size="large">
<RadioButton value="a">赵六</RadioButton>
<RadioButton value="b">李四</RadioButton>
<RadioButton value="c">王五</RadioButton>
<RadioButton value="d">张三</RadioButton>
{shows}
</RadioGroup>
</FormItem>
</p>
);
},
});
巴扎黑2017-04-17 15:10:43
JSX里的{}不能直接用for
,而且值要出来不用再加花括号,这代码有明显的错误。
要像这样才行,下面用箭头函数包起来,直接用函数也行:
<p>
{()=> { for(var i=1; i<10; i++){
<p>i</p>
}
}
}
</p>
不过一般如果到render中的return语句,应该要在这之前先求出值再进去加在花括号中。而不是在里面作运算。
PHP中文网2017-04-17 15:10:43
var items = this.props.appointExpertPostFormReduce.map((item, i)=>{
return (
<RadioButton></RadioButton>
{/***/}
);
});