Bilangan tempat perpuluhan dalam data mengelirukan apabila Python memproses siri masa

Question

Saya ingin membahagikan siri masa kepada keadaan Nilai maksimum siri masa ialah 1.8 dan nilai minimum ialah -0.5 Ia dibahagikan kepada 115 selang keadaan selang ditukar kepada nilai di tengah selang Saya menulis sekeping kod, tetapi bilangan tempat perpuluhan dalam nilai yang diperolehi adalah sangat pelik, tolong bantu saya menyelesaikan masalah, terima kasih

.

__author__ = 'Administrator'
file = open('yij.txt','r')

while 1:
    line = file.readline()
    a = line.split()
    m=0
    b=[-0.5,-0.48,-0.46,-0.44,-0.42,-0.40,-0.38,-0.36,-0.34,-0.32,-0.30,-0.28,-0.26,-0.24,-0.22,-0.20,-0.18,-0.16,-0.14,-0.12,-0.10,-0.08,-0.06,-0.04,-0.02,0.00,0.02,
   0.04,0.06,0.08,0.10,0.12,0.14,0.16,0.18,0.20,0.22,0.24,0.26,0.28,0.30,0.32,0.34,0.36,0.38,0.40,0.42,0.44,0.46,0.48,0.50,0.52,0.54,0.56,0.58,0.60,0.62,0.64,
   0.66,0.68,0.70,0.72,0.74,0.76,0.78,0.80,0.82,0.84,0.86,0.88,0.90,0.92,0.94,0.96,0.98,1.00,1.02,1.04,1.06,1.08,1.10,1.12,1.14,1.16,1.18,1.20,1.22,1.24,1.26,1.28,
   1.30,1.32,1.34,1.36,1.38,1.40,1.42,1.44,1.46,1.48,1.50,1.52,1.54,1.56,1.58,1.60,1.62,1.64,1.66,1.68,1.70,1.72,1.74,1.76,1.78,1.80]
    if line != '':
        file1 = open('yij_state.txt', 'a+')
        for i in b:
            if i<float(a[0])<=i+0.02:
                file1.write("%.2f\n" % (i+0.01))
            if float(a[0])<=-0.5:
                file1.write("%.2f\n" % (-0.49))
            elif float(a[0])>1.8:
                file1.write("%.2f\n" % (1.79))
                break
        file1.close
    else:
        break
file.close

Kod telah diperbetulkan

Answer 1

Cukup simpan dua tempat perpuluhan