Gambar crawler - Sila beritahu saya: masalah pengekodan perangkak python, versi 3.6, win10 64-bit?

Question

Ini ialah mesej ralat:

Traceback (most recent call last):
  File "D:\py\pic_downfrom2255ok.py", line 45, in <module>
    html = getHtml(url_all[i])
  File "D:\py\pic_downfrom2255ok.py", line 32, in getHtml
    html = response.read().decode()
UnicodeDecodeError: 'utf-8' codec can't decode byte 0xb3 in position 184: invalid start byte

Banyak yang telah diubah Sebab utama mungkin tapak web sasaran dikodkan dalam gb2312
Program ini boleh memuat turun gambar secara normal di laman web lain, tetapi akan ada masalah apabila beralih ke laman web semasa beberapa nasihat. Saya mencuba beberapa kaedah tetapi tiada yang berjaya Kod sumber adalah seperti berikut:

#coding=utf-8
import urllib.request
from urllib.request import urlopen, urlretrieve 
import urllib
import urllib.parse
import re
import os
from bs4 import BeautifulSoup


url_all =[
'http://www.shop2255.com/showpro/2603.html',
'http://www.shop2255.com/showpro/1558.html',
'http://www.shop2255.com/showpro/1564.html',
'http://www.shop2255.com/showpro/2411.html',
'http://www.shop2255.com/showpro/2409.html',
'http://www.shop2255.com/showpro/1561.html',
'http://www.shop2255.com/showpro/2414.html',
'http://www.shop2255.com/showpro/2609.html',
'http://www.shop2255.com/showpro/2413.html',
'http://www.shop2255.com/showpro/2604.html',
'http://www.shop2255.com/showpro/2605.html',
'http://www.shop2255.com/showpro/2606.html',
'http://www.shop2255.com/showpro/2608.html',
'http://www.shop2255.com/showpro/2607.html',
'http://www.shop2255.com/showpro/2610.html']

def getHtml(url):
    response = urlopen(url)
    html = response.read().decode("gbk")
    return html


def getImg(html):
    reg = 'src="(.+?\.jpg)"'
    imgre = re.compile(reg)
    imglist = re.findall(imgre,html)

    return imglist

for i in range(len(url_all)):
    html = getHtml(url_all[i])
    list=getImg(html.decode())
    x = 0
    for imgurl in list:
        print(x)
        file_path = url_all[i]
        (filepath,tempfilename) = os.path.split(file_path)
        (filename,extension) = os.path.splitext(tempfilename)
        
        if not os.path.exists('d:\%s' % filename):
            os.mkdir('d:\%s' % filename)
        # os.mkdir('D:\%s' % filename2)
        
        local=r'D:\%s\%s.jpg' % (filename,imgurl.splite("/")[-1])
        urllib.request.urlretrieve(imgurl,local)
        x+=1
print("done")

Answer 1

# coding: utf-8

import urllib
import requests
from pyquery import PyQuery as Q
import os

base_url = 'http://www.shop2255.com/'


url_all =['http://www.shop2255.com/showpro/2603.html']


for url in url_all:
    _, file_name = os.path.split(url)
    dir_name, _ = os.path.splitext(file_name)

    if not os.path.exists(dir_name):
        os.mkdir(dir_name)

    r = requests.get(url)
    for _ in Q(r.text).find('img'):
        src = Q(_).attr('src')
        image_url = src if src.startswith('http') else os.path.join(base_url, src)
        _, image_name = os.path.split(image_url)

        image_path = os.path.join(dir_name, image_name)
        urllib.urlretrieve(image_url, image_path)

Answer 2

Pertama, dalam kod anda local=r'D:%s%s.jpg' % (nama fail,imgurl.splite("/")[-1])split< /code > ditulis sebagai splite local=r'D:%s%s.jpg' % (filename,imgurl.splite("/")[-1])中split写成了splite.

还有 urllib.request.urlretrieve(imgurl,local)这个imgurl不是一个合法的
url,只是一个相对 url, 要改成绝对 url,需要加上 base_url = 'http://www.shop2255.com/'

Juga urllib.request.urlretrieve(imgurl,local) imgurl ini bukan url
sah, hanya url relatif, Kepada tukar kepada url mutlak, anda perlu menambah base_url = 'http://www.shop2255.com/'

Nampaknya juga terdapat masalah dengan laluan fail yang dijana.🎜

# -*- coding: utf-8 -*-

import urllib.request
from urllib.request import urlopen, urlretrieve
import urllib
import urllib.parse
import re
import os
from bs4 import BeautifulSoup

base_url = 'http://www.shop2255.com/'

url_all =[
'http://www.shop2255.com/showpro/2603.html',
'http://www.shop2255.com/showpro/1558.html',
'http://www.shop2255.com/showpro/1564.html',
'http://www.shop2255.com/showpro/2411.html',
'http://www.shop2255.com/showpro/2409.html',
'http://www.shop2255.com/showpro/1561.html',
'http://www.shop2255.com/showpro/2414.html',
'http://www.shop2255.com/showpro/2609.html',
'http://www.shop2255.com/showpro/2413.html',
'http://www.shop2255.com/showpro/2604.html',
'http://www.shop2255.com/showpro/2605.html',
'http://www.shop2255.com/showpro/2606.html',
'http://www.shop2255.com/showpro/2608.html',
'http://www.shop2255.com/showpro/2607.html',
'http://www.shop2255.com/showpro/2610.html']

def getHtml(url):
    response = urlopen(url)
    # print(response.read())
    html = response.read().decode("gbk")
    print(html)
    return html


def getImg(html):
    reg = 'src="(.+?\.jpg)"'
    imgre = re.compile(reg)
    imglist = re.findall(imgre, html)
    return imglist

for i in range(len(url_all)):
    html = getHtml(url_all[i])
    # 注意: 我这里没有你那个错误,我只需要改这个就行了
    # list = getImg(html.decode())
    list = getImg(html)
    # print(list)
    x = 0
    for imgurl in list:
        print(x)
        file_path = url_all[i]
        (filepath, tempfilename) = os.path.split(file_path)
        (filename, extension) = os.path.splitext(tempfilename)

        if not os.path.exists('d:\%s' % filename):
            os.mkdir('d:\%s' % filename)
        # os.mkdir('D:\%s' % filename2)

        local = r'D:\%s\%s.jpg' % (filename, imgurl.split("/")[-1])
        try:
            urllib.request.urlretrieve(base_url + imgurl, local)
        except:
            print("can't retrieve the" + base_url + imgurl)
        x += 1

print("done")