Rumah >pembangunan bahagian belakang >Golang >Cara untuk membetulkan isu ini: Panik: Penyegerakan: Kaunter WaitGroup Negatif
Saya kadang-kadang menghadapi masalah ini selepas menjalankannya berulang kali. Saya tahu ini berkaitan dengan kaunter. Ia membuang ralat ini apabila kaedah done() sync.waitgroup dipanggil lebih banyak kali daripada kaedah add() dipanggil.
Bagaimana untuk menyelesaikan masalah ini?
Kod saya mencipta kelompok bersaiz 4 dan melakukan beberapa pemprosesan pada setiap kelompok, tetapi saya menghadapi masalah untuk menyelesaikan panik ini.
package main import ( "fmt" "sync" ) func main() { // create input channel input := make(chan int) // create wait group var wg sync.waitgroup // start batcher goroutine wg.add(1) go batcher(input, &wg) // send input values to the batcher for i := 1; i <= 10; i++ { input <- i } // close input channel close(input) // wait for batcher goroutine to finish wg.wait() } func batcher(input chan int, wg *sync.waitgroup) { // create batch channel with buffer of size 4 batch := make(chan int, 4) // create channel to synchronize worker goroutines done := make(chan bool) // create wait group for worker goroutines var workerwg sync.waitgroup // start worker goroutines for i := 0; i < 4; i++ { workerwg.add(1) go worker(batch, &workerwg, done) } // read input values and send to batch for value := range input { batch <- value if len(batch) == 4 { // wait for worker goroutines to finish processing batch workerwg.wait() // send batch to worker goroutines for i := 0; i < 4; i++ { workerwg.add(1) go sendbatch(batch, &workerwg, done) } } } // wait for worker goroutines to finish processing remaining batch workerwg.wait() // close done channel to notify that all batches have been processed close(done) wg.done() } func sendbatch(batch chan int, workerwg *sync.waitgroup, done chan bool) { // process batch for value := range batch { fmt.println("processing value:", value) } // notify worker goroutines that batch has been processed workerwg.done() select { case done <- true: default: // done channel has been closed } } func worker(batch chan int, workerwg *sync.waitgroup, done chan bool) { // process batches received from batch channel for batch := range batch { // process batch fmt.println("processing batch:", batch) workerwg.done() } // notify batcher goroutine that worker goroutine has finished select { case done <- true: default: // done channel has been closed } }
Kod asas untuk menulis program kelompok:
package main import ( "fmt" "sync" ) func main() { input := make(chan int) output := make(chan []int) var wg sync.waitgroup wg.add(2) // start the batcher goroutine go func() { batch := []int{} for value := range input { batch = append(batch, value) if len(batch) == 4 { output <- batch batch = []int{} } } if len(batch) > 0 { output <- batch } close(output) wg.done() }() // start the worker goroutine go func() { for batch := range output { sum := 0 for _, value := range batch { sum += value } fmt.printf("sum of batch %v: %d\n", batch, sum) } wg.done() }() // send input values to the batcher for _, v := range []int{1, 2, 3, 4, 5, 6, 7, 8, 9, 10} { input <- v } close(input) // wait for both goroutines to finish wg.wait() }
Sum of batch [1 2 3 4]: 10 Sum of batch [5 6 7 8]: 26 Sum of batch [9 10]: 19
Reka bentuk awal agak kompleks, saya akan cuba kembangkan pada reka bentuk asas ini.
Mengikut kod ini:
for i := 0; i < 4; i++ { workerwg.add(1) go worker(batch, &workerwg, done) }
Saya rasa workerwg.done()
harus dialihkan ke luar gelung:
func worker(batch chan int, workerWg *sync.WaitGroup, done chan bool) { + defer workerWg.Done() // process batches received from batch channel for batch := range batch { // process batch fmt.Println("Processing batch:", batch) - workerWg.Done() } // notify batcher goroutine that worker goroutine has finished select { case done <- true: default: // done channel has been closed } }
Tetapi batch
tidak ditutup dalam demo. Jadi sebenarnya, goroutine akan berjalan selama-lamanya sehingga program tamat.
Tidak pasti jika terdapat sebarang soalan lain. Reka bentuknya terlalu kompleks. Kod kompleks sukar difahami dan terdedah kepada ralat. Pertimbangkan untuk mereka bentuk semula.
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