Rumah >pembangunan bahagian belakang >Tutorial Python >Bagaimana untuk melaksanakan permainan catur tiga keping dalam python
Logik pelaksanaan permainan catur tiga keping adalah seperti berikut:
1 Buat papan catur 3*3
2 memegang kepingan U dan menggerakkan kepingan terlebih dahulu; membuat langkah;
5. Penentuan kemenangan atau kekalahan, jika kemenangan adalah Jika keputusan negatif, teruskan dari langkah 2
2. Langkah asas
def menu(): print('-'*20) print('1---------------begin') print('2---------------exit') print('please select begin or exit') print('-' * 20) while(1): select = input('please input:') if select == '1': begin_games() pass elif select == '2': print('exit the game') break #pass pass
chess_board = [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
def init_cheaa_board(chess_board): #先对列表进行初始化 for i in range(MAX_ROW): for j in range(MAX_COL): chess_board[i][j] = ' ' pass def print_chess_board(chess_board): #棋盘打印 print('*'+'-'*7+'*'+'-'*7+'*'+'-'*7+'*') for i in range(MAX_ROW): print('|'+' '*3+chess_board[i][0]+' '*3+'|'+' '*3+chess_board[i][1]+' '*3+'|'+' '*3+chess_board[i][2]+' '*3+'|') print('*' + '-' * 7 + '*' + '-' * 7 + '*' + '-' * 7 + '*') pass pass
3. Pemain membuat pergerakan
Pemain memilih koordinat mendatar dan menegak pergerakan pada papan catur 3*3. Titik koordinat perlu memenuhi keperluan berikut: 1. Titik berada dalam papan catur 2. Titik belum diletakkan.def player_first(chess_board): while(1): x = int(input('please input x:')) y = int(input('please input y:')) if(chess_board[x][y] != ' '): #若已被置子,则重新选择坐标 print('This position is already occupied!') pass elif(x >= MAX_ROW or y >= MAX_COL or x < 0 or y < 0): #所选坐标超出棋盘范围,重新选择坐标 print('This position is beyond the chessboard!') pass else: #若坐标可以落子,则将该坐标置为玩家的棋子U chess_board[x][y] = 'U' print_chess_board(chess_board) #return x,y break pass pass
C Titik berfaedah terakhir ialah bahagian tengah setiap sisi, yang akan menyekat dua laluan pemain; 🎜>Keputusan akhir: Kalah, menang, seri D
Proses penentuan: Tentukan sama ada terdapat pemain U atau komputer T pada setiap garisan melintang, garisan menegak, dan garisan pepenjuru untuk membentuk tiga menang; apabila seluruh permukaan catur diduduki tetapi pemain mahupun komputer tidak berjaya, ia bermakna seri.def Intercept_player(chess_board,key): count2 = 0 index2 = [] intercept_index = {'x':-1,'y':-1} for i in range(MAX_ROW): index = [] count = 0 count1 = 0 index1 = [] allindex = [0,1,2] for j in range(MAX_ROW): if(chess_board[i][j] == key): #每一行的玩家落子情况 count += 1 index.append(j) if(chess_board[j][i] == key): #每一列的玩家落子情况 #print('j'+str(j)+',i'+str(i)+'='+chess_board[j][i]) count1 += 1 index1.append(j) if (i == j and chess_board[j][i] == key): # 在主对角线中的玩家落子情况 count2 += 1 index2.append(j) if(count == 2): #在每一行中 获取具体的可以拦截的位置坐标 需要排除掉已经填充的位置 result = list(set(allindex).difference(set(index))) result = result[0] if(chess_board[i][result] == ' '): #当这个位置可以进行拦截时,进行坐标返回 #return i,result intercept_index['x'] = i intercept_index['y'] = result return intercept_index #print(count1,'------->',index1) if (count1 == 2): # 在每一列中 获取具体的可以拦截的位置坐标 需要排除掉已经填充的位置 result = list(set(allindex).difference(set(index1))) result = result[0] #print('count1==2,result:',result) if (chess_board[result][i] == ' '): # 当这个位置可以进行拦截时,进行坐标返回 intercept_index['x'] = result intercept_index['y'] = i return intercept_index #return i, result if (count2 == 2): # 在主对角线上 获取具体的可以拦截的位置坐标 需要排除掉已经填充的位置 result = list(set(allindex).difference(set(index2))) result = result[0] if (chess_board[i][result] == ' '): # 当这个位置可以进行拦截时,进行坐标返回 intercept_index['x'] = i intercept_index['y'] = result return intercept_index #return i, result count3 = 0 if(chess_board[0][2] == key): count3 += 1 if (chess_board[1][1] == key): count3 += 1 if (chess_board[2][0] == key): count3 += 1 if(count3 == 2): if(chess_board[0][2] == ' '): intercept_index['x'] = 0 intercept_index['y'] = 2 elif (chess_board[1][1] == ' '): intercept_index['x'] = 1 intercept_index['y'] = 1 elif (chess_board[2][0] == ' '): intercept_index['x'] = 2 intercept_index['y'] = 0 return intercept_index def computer_second(chess_board): #电脑智能出棋 #1、先检查一下电脑是否两子成棋 若已有,则获取空位置坐标 自己先成棋 intercept_index = Intercept_player(chess_board, 'T') if (intercept_index['x'] == -1 and intercept_index['y'] == -1): pass else: # 电脑可落子 x = intercept_index['x'] y = intercept_index['y'] chess_board[x][y] = 'T' return #2、若玩家快成棋 则先进行拦截 intercept_index = Intercept_player(chess_board,'U') #若玩家已经两子成棋 则获取空位置的坐标 #print('intercept_index---:') #print(intercept_index) if(intercept_index['x'] == -1 and intercept_index['y'] == -1): pass else: #电脑可落子 x = intercept_index['x'] y = intercept_index['y'] chess_board[x][y] = 'T' return #3、如果没有,则电脑端排棋 以促进成棋 #3.1、 占领中心位置 如若中心位置[1,1]未被占领 if(chess_board[1][1] == ' '): chess_board[1][1] = 'T' return #3.2、 占领四角位置 若[0,0] [0,2] [2,0] [2,2]未被占领 if (chess_board[0][0] == ' '): chess_board[0][0] = 'T' return if (chess_board[0][2] == ' '): chess_board[0][2] = 'T' return if (chess_board[2][0] == ' '): chess_board[2][0] = 'T' return if (chess_board[2][2] == ' '): chess_board[2][2] = 'T' return # 3.3、 占领每一边中心位置 若[0,1] [1,0] [1,2] [2,1]未被占领 if (chess_board[0][1] == ' '): chess_board[0][1] = 'T' return if (chess_board[1][0] == ' '): chess_board[1][0] = 'T' return if (chess_board[1][2] == ' '): chess_board[1][2] = 'T' return if (chess_board[2][1] == ' '): chess_board[2][1] = 'T' return3. Kod keseluruhan
def chess_board_isfull(chess_board): #判断棋盘是否填充满 for i in range(MAX_ROW): if (' ' in chess_board[i]): return 0 return 1 pass def Win_or_lose(chess_board): isfull = chess_board_isfull(chess_board) for i in range(MAX_ROW): #每一列的判断 if( chess_board[0][i] == chess_board[1][i] == chess_board[2][i]): return chess_board[0][i] pass pass for i in range(MAX_ROW): # 每一行的判断 if( chess_board[i][0] == chess_board[i][1] == chess_board[i][2]): return chess_board[i][0] pass pass if (chess_board[0][0] == chess_board[1][1] == chess_board[2][2]): # 判断棋盘正对角线 return chess_board[0][0] if (chess_board[0][2] == chess_board[1][1] == chess_board[2][0]): # 判断棋盘反对角线 return chess_board[0][2] if isfull: return 'D' # 经过以上的判断,都不满足(既没赢也没输),但是棋盘也已经填充满,则说明和棋 else: return ' '
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