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实现改变状态和删除无刷新的Ajax+PHP代码

php中世界最好的语言asal: 2018-03-30 15:42:452284semak imbas

这次给大家带来实现改变状态和删除无刷新的Ajax+PHP代码，实现改变状态和删除无刷新Ajax+PHP的注意事项有哪些，下面就是实战案例，一起来看一下。

1. 01.php为主程序，调用smarty模板遍历输出：

<?php
  include &#39;./include/Mysql.class.php&#39;;
  include &#39;./libs/Smarty.class.php&#39;;
  $db=new Mysql;
  $smarty=new Smarty;
  $lists=$db->getALL('users');
  $smarty->assign('lists',$lists);
  $smarty->display('list.html');
?>

2. list.html模板:内容结合JS ajax使用：

<!DOCTYPE html>
<html>
<head>
  <meta charset=utf-8>
  <title>用户权限展示表</title>
</head>
<body>
    //给table体设置一个p，方便js调用
    <p id="table">
    <table align="center" border="1" width="500">
      <center><h2>用户权限表</h2></center>
      <tr>
        <th>uid</th><th>用户名</th><th>密码</th><th>锁定状态</th><th>角色</th><th>操作</th>
      </tr>  
      {foreach $lists as $list}
        <tr align="center">
          <td>{$list.uid}</td>
          <td>{$list.username}</td>
          <td>{$list.password}</td>
          {if $list.is_lock==1}
            <td><a href="javascript:lock(0,{$list.uid});" rel="external nofollow" >锁定</a></td>
            {else}
            <td><a href="javascript:lock(1,{$list.uid})" rel="external nofollow" ;>取消锁定</a></td>  
          {/if}    
          {if $list.role==1}
              <td>管理员</td>
          {else}
              <td>编辑者</td>    
          {/if}
          <td><a href="javascript:del({$list.uid})" rel="external nofollow" >删除</a></td>
        </tr>    
      {/foreach}  
    </table>
    </p>  
</body>
    <script type="text/javascript">
      function lock(lock,uid){
          //创建ajax对象
          var xhr=new XMLHttpRequest();
          //打开一个链接
          xhr.open('post','02.php');
          //设置头信息
          xhr.setRequestHeader('content-type','application/x-www-form-urlencoded');
          //取值,多个参数用&分开
          var data="is_lock="+lock+"&uid="+uid;
          //发送ajax数据请求
          xhr.send(data);
          //设置回调、监听函数
          xhr.onreadystatechange=function(){
            //如果ajax状态码响应正常且网络正常，获取响应文本
            if(xhr.readyState==4&&xhr.status==200){
              if(xhr.responseText){
                document.getElementById('table').innerHTML=xhr.responseText;
              }else{
                alert("切换状态失败！");
              }
            }
          }
        }
    function del(uid){
      var del=window.confirm("您确定要删除吗？");
      if(del){
        //创建ajax对象
        var xhr=new XMLHttpRequest();
        //打开一个链接
        xhr.open('post','del.php');
        //设置header头
        xhr.setRequestHeader('content-type','application/x-www-form-urlencoded');
        //data取值
        var data="uid="+uid;
        //发送ajax请求
        xhr.send(data);
        //设置监听
        xhr.onreadystatechange=function(){
          //如果ajax状态码响应正常且网络正常，获取响应文本
          if(xhr.readyState==4&&xhr.status==200){
            if(xhr.responseText){
              //用ajax响应内容替换本模板中table标签的内容
              document.getElementById('table').innerHTML=xhr.responseText;
            }else{
              alert("删除失败！");
            }
          }
        }
      }
    }    
    </script>
</html>

3. 02.php改变状态无刷新：

<?php
  include &#39;./include/Mysql.class.php&#39;;
  include &#39;./libs/Smarty.class.php&#39;;
  $lock=$_POST[&#39;is_lock&#39;];
  $uid=$_POST[&#39;uid&#39;];
  $smarty=new Smarty;
  $db=new Mysql;
  $result=$db->update('users',"is_lock=$lock","uid=$uid");
  if($result){
    //修改成功重新遍历数据库并输出smarty模板
    $lists=$db->getALL('users');
    $smarty->assign('lists',$lists);
    $smarty->display('list.html');
  }else{
    echo false;
  }
?>

4.del.php实现删除无刷新

<?php
  include &#39;./include/Mysql.class.php&#39;;
  include &#39;./libs/Smarty.class.php&#39;;
  $db=new Mysql;
  $smarty=new Smarty;
  $uid=$_POST[&#39;uid&#39;];
  $res=$db->delete('users',$uid);
  if($res>0){
    $lists=$db->getALL('users');
    $smarty->assign('lists',$lists);
    $smarty->display('list.html');
  }else{
    echo false;
  }
?>

相信看了本文案例你已经掌握了方法，更多精彩请关注php中文网其它相关文章！

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