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PHP+MySQL实现的简单投票系统实例_php技巧

WBOY
WBOYasal
2016-05-16 19:58:151594semak imbas

本文实例讲述了PHP+MySQL实现的简单投票系统。分享给大家供大家参考，具体如下：

<html>
<head><title>手机系统调查问卷</title>
<style type="text/css">
<!--
span{
  width:600px;
  height:100px;
  background-color:write;
  postion:relative;
  border:1px #cccccc solid;
}
div{
  width:60px;
  height:1px;
  background-color:blue;
  postion:absolute;
  bottom:0;
}
-->
</style>
</head>
<body>
你现在使用的手机是什么系统？
<form id="form1" method="POST" action="count.php">
<input type="radio" name="phone" value="1"> Android安卓
<input type="radio" name="phone" value="2"> Symbian塞班
<br>
<input type="radio" name="phone" value="3"> iphone苹果
<input type="radio" name="phone" value="4"> Google谷歌
<br>
<input type="radio" name="phone" value="5"> Winphone微软
<input type="radio" name="phone" value="6"> 其它
<br>
<input type="submit" value="提交">
</form>
<span>
当前票数：<br>
<&#63;php
include 'connect.php';
$sql="select answer from countone";
$rs=mysql_query($sql);
$total=mysql_num_rows($rs);
$sql="select * from countone where answer=1";
$rs=mysql_query($sql);
$android=mysql_num_rows($rs);
$sql="select * from countone where answer=2";
$rs=mysql_query($sql);
$symbian=mysql_num_rows($rs);
$sql="select * from countone where answer=3";
$rs=mysql_query($sql);
$iphone=mysql_num_rows($rs);
$sql="select * from countone where answer=4";
$rs=mysql_query($sql);
$google=mysql_num_rows($rs);
$sql="select * from countone where answer=5";
$rs=mysql_query($sql);
$winphone=mysql_num_rows($rs);
$sql="select * from countone where answer=6";
$rs=mysql_query($sql);
$other=mysql_num_rows($rs);
&#63;>
<table border="0">
<th>android</th><th>Symbian</th><th>iphone</th><th>Google</th><th>winphone</th><th>other</th>
<tr>
<td><&#63;php echo $android &#63;>票</td>
<td><&#63;php echo $symbian &#63;>票</td>
<td><&#63;php echo $iphone &#63;>票</td>
<td><&#63;php echo $google &#63;>票</td>
<td><&#63;php echo $winphone &#63;>票</td>
<td><&#63;php echo $other &#63;>票</td>
</tr>
<tr>
<td><&#63;php for ($i=1;$i<=$android/$total+1;$i=$i+0.1){  echo "<div></div>"; } &#63;></td>
<td><&#63;php for ($i=1;$i<=$symbian/$total+1;$i=$i+0.1){  echo "<div></div>"; } &#63;></td>
<td><&#63;php for ($i=1;$i<=$iphone/$total+1;$i=$i+0.1){  echo "<div></div>"; } &#63;></td>
<td><&#63;php for ($i=1;$i<=$google/$total+1;$i=$i+0.1){  echo "<div></div>"; } &#63;></td>
<td><&#63;php for ($i=1;$i<=$winphone/$total+1;$i=$i+0.1){ echo "<div></div>"; } &#63;></td>
<td><&#63;php for ($i=1;$i<=$other/$total+1;$i=$i+0.1){ echo "<div></div>"; } &#63;></td>
</tr>
</table>
</span>
</body>
</html>

写的有点啰嗦，有点笨但很实用

<&#63;php
include 'connect.php';
$name=$_POST['phone'];
$sql="insert into countone values(null,$name,now(),null)";
mysql_query($sql);
&#63;>
<script type="text/javascript">
 alert ("投票成功！");
 location="question.php";
</script>

链接mysql：

<&#63;php
mysql_connect("localhost","root","");
mysql_select_db("vote");
mysql_query("set names utf8");
&#63;>

更多关于PHP相关内容感兴趣的读者可查看本站专题：《php面向对象程序设计入门教程》、《php字符串(string)用法总结》、《php+mysql数据库操作入门教程》及《php常见数据库操作技巧汇总》

希望本文所述对大家PHP程序设计有所帮助。

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