Rumah > Artikel > hujung hadapan web > Codeforces Beta Round #25 (Div. 2)A. IQ test_html/css_WEB-ITnose
IQ test
time limit per test
2 seconds
memory limit per test
256 megabytes
input
standard input
output
standard output
Bob is preparing to pass IQ test. The most frequent task in this test is to find out which one of the given n numbers differs from the others. Bob observed that one number usually differs from the others in evenness. Help Bob ? to check his answers, he needs a program that among the given n numbers finds one that is different in evenness.
Input
The first line contains integer n (3?≤?n?≤?100) ? amount of numbers in the task. The second line contains n space-separated natural numbers, not exceeding 100. It is guaranteed, that exactly one of these numbers differs from the others in evenness.
Output
Output index of number that differs from the others in evenness. Numbers are numbered from 1 in the input order.
Sample test(s)
input
52 4 7 8 10
output
input
41 2 1 1
output
解题报告:水题。。。给你一列数,其中只有一个数的奇偶性和其他数不同,输出它所在的位置。直接暴力扫一遍,记录最后一个奇数和偶数的位置,并记录奇数和偶数的个数,即可。
AC代码:
#include <stdio.h>#include <string.h>#include <iostream>#include <algorithm>#include <vector>#include <queue>#include <set>#include <map>#include <string>#include <math.h>#include <stdlib.h>#include <time.h>using namespace std;#define INF 0x7fffffffint a[105];int main(){ #ifdef sxk freopen("in.txt","r",stdin); #endif int n; while(scanf("%d",&n)!=EOF) { int ans1 = 0, ans2 = 0, x, y; for(int i=0; i<n i cin>>a[i]; if(a[i]&1) { ans1 ++; x = i+1; } else{ ans2 ++; y = i+1; } } if(ans1>ans2) cout <br> <br> <p></p> <p><br> </p> <p><br> </p> <p><br> </p> <p><br> </p> </n></time.h></stdlib.h></math.h></string></map></set></queue></vector></algorithm></iostream></string.h></stdio.h>