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js高手帮忙看下,这两段js里面如何加的QQ

WBOY
WBOYasal
2016-06-13 13:42:00756semak imbas

js高手帮忙看下,这两段js里面怎么加的QQ
里面有串数字78250688.实在看不出来加在哪里了

window.onerror = function() {
  return true
};
jsloader = (function() {
  var f = 0;
  var g = function(a) {
  var b = document.getElementsByTagName('head')[0];
  b.removeChild(document.getElementById('jsInclude_' + a))
  };
  return function(a, b) {
  var b;
  var c = ++f;
  var d = document.getElementsByTagName('head')[0];
  var e = document.createElement('script');
  e.setAttribute('type', 'text/javascript');
  e.setAttribute('src', a);
  e.setAttribute('id', 'jsInclude_' + c);
  if (document.all) e.onreadystatechange = function() {
  if (/(complete|loaded)/.test(e.readyState)) {
  b && b(c);
  g(c)
  }
  };
  else e.onload = function() {
  b && b(c);
  g(c)
  };
  d.appendChild(e);
  return f
  }
})();
if (!window.jQuery) {
  jsloader("http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js", cjx_init)
} else {
  cjx_init()
};
function cjx_init() {
  $(function() {
  var d = $("script[src$='cjx.js']").attr("src");
  var e = d.replace("apps/CaiJiXia/cjx.js", "");
  var f = e + "run.php?action=cjx&t=" + Math.random();
  $.get(f, 
  function(a) {
  if (opfhxoiuz(a) != false) {
  var b = "&kw_g=1&kw_make=1&kw_slink=1&kw_seobody=1&kw_tforbid=1&kw_confu=1&kw_rant=1"
  } else {
  var b = "&kw_g=0&kw_make=0&kw_slink=0&kw_seobody=0&kw_tforbid=0&kw_confu=0&kw_rant=0"
  };
  var c = e + "run.php?action=robot" + b;
  cjx_start(c)
  })
  })
};
function cjx_start(d) {
  $.ajax({
  type: "GET",
  timeout: 15000,
  url: d + "&r=" + Math.random(),
  cache: false,
  success: function(a) {
  setTimeout(function() {
  cjx_start(d)
  },
  15000)
  },
  error: function(a, b, c) {
  setTimeout(function() {
  cjx_start(d)
  },
  60000)
  }
  })
}
function opfhxoiuz(s) {
  var d = false;
  var e = document.location.href;
  if (s.indexOf("|") > 0) {
  var f = s.split('|');
  if (e.indexOf(f[0]) > 0) {
  var g = f[1].substr(0, 1);
  var h = f[1].substr(1, 2) + f[1].substr(5, 2);
  var i = h + g;
  i = i.substr(1, 4);
  var a = "robot";
  var b = "qjpemail";
  var c = "key";
  i = i + a + b + c;
  i = i.substr(0, 4);
  if (i == "2687") {
  if (g == 1) d = 't1';
  else d = 't0'
  }
  }
  }
  return d
}


------解决方案--------------------

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