Rumah >pembangunan bahagian belakang >tutorial php > mysql数据库中2个表建立关系解决思路
mysql数据库中2个表建立关系
表1 page:(page_id,page_text,img_exist)=>(页面id,页面内容,是否存在图片1存在,0不存在)
表2 image:(img_id,img_name)=>(图片id,图片名)
现在表2增加1列: image:(img_id,img_name,page_id)
现在要求是 把页面中含有的图片全部归类到属于哪一个页面id。
<!-- Code highlighting produced by Actipro CodeHighlighter (freeware) http://www.CodeHighlighter.com/ --> <?php $DBserver = "localhost"; $DBname = "new"; $DBuser = "root"; $DBpassword = ""; $con = mysql_connect("localhost","root",""); mysql_select_db("new"); $query = mysql_query("select page_id,page_text from pagecontents where img_exist > 0") or die(mysql_error() ); while($rows = mysql_fetch_array($query)) { $pid = $rows['page_id']; $ptext = $rows['page_text']; $ptext = mysql_real_escape_string($ptext); $ptext = preg_replace('/poweredby_mediawiki_88x31\.png/s','',$ptext); if(preg_match_all('/.+\.(gif|swf|jpg|png)/is',$ptext,$match)){ $ptext = $match[1][0]; $ptext = mysql_real_escape_string($ptext); } mysql_select_db("lookdb",$con); $sql = "update imgmulu set page_id = ('{$pid}') where img_name = ('{$ptext}')"; mysql_query($sql) or die(mysql_error()); } ?>