一个关于php构建测试表单的有关问题

求助一个关于php构建测试表单的问题

PHP code

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<?php $con=mysql_connect("localhost","root","");
mysql_select_db("test");
mysql_query("set names gb2312");
?>

这是初始的服务器config.

PHP code

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<?php error_reporting(E_ALL & ~ E_NOTICE);
echo "<center>";
if (!$_POST["test_name"])
{
    echo "<h2>create test</h2>";
    echo "

"; echo ""; echo ""; echo ""; echo ""; echo ""; echo ""; echo ""; echo ""; echo ""; echo "

test question

"; } else { include 'config.php'; $content=$_POST["test_name"]; $sql="insert into question('content') values('$content')"; if (mysql_query($sql)) { echo "create test_content successfull!!!"; echo "

"; echo "clickhereto add question"; } else "error!!!".mysql_error(); mysql_close(); } echo "

"; ?>

现在问题是这样的,创建不了表单,求大神帮我指点指点...为什么会出现这样的状况..谢谢了

------解决方案--------------------
$sql="insert into question(`content`) values('$content')"; //content的注释符号写错了