Ringkasan javascript bubble sort_basic knowledge

Contoh isihan gelembung, isihan gelembung dua hala dan visualisasi isihan gelembung dua hala yang dipertingkatkan sedikit.

Kod ini sangat mudah, saya tidak tahu sama ada terdapat sebarang pepijat yang tidak diketahui.
Tuhan, tolong jangan mengeluh

Contoh isihan gelembung

var ls=[ 98,13,6,25,38,36,30,44,38,80,61,28,47,34,95,18,85,58,89,85,42,61,74,35,13,14,80,7,10,44,10,47,13,11,52,25,24,48,34,12,88,80,33,8,80,45,64,52,79,77 ];
 
for(var i=0;i<ls.length;i++){
      for(var j=i+1;j<ls.length;j++){
        if(ls[i]>ls[j]){
          ls[i]=ls[i]+ls[j];
          ls[j]=ls[i]-ls[j];
          ls[i]=ls[i]-ls[j];
        } 
      }
    }

Contoh isihan gelembung dua hala

var ls=[ 6,13,98,25,38,36,30,44,38,80,61,28,47,34,95,18,85,58,89,85,42,61,74,35,13,14,80,7,10,44,10,47,13,11,52,25,24,48,34,12,88,80,33,8,80,45,64,52,79,77 ];
 
for(var i=0;i<ls.length;i++){
      for(var j=i+1;j<ls.length-i;j++){
        if(ls[lent-1-i]<ls[lent-j]){
          ls[lent-1-i]=ls[lent-1-i]+ls[lent-j];
          ls[lent-j]=ls[lent-1-i]-ls[lent-j];
          ls[lent-1-i]=ls[lent-1-i]-ls[lent-j];
        }//后面的比较
        if(ls[i]>ls[j]){
          ls[i]=ls[i]+ls[j];
          ls[j]=ls[i]-ls[j];
          ls[i]=ls[i]-ls[j];
        }//前面的比较
      }
    }

Contoh isihan gelembung dua hala yang dipertingkatkan sedikit

var ls=[ 98,13,6,25,38,36,30,44,38,80,61,28,47,34,95,18,85,58,89,85,42,61,74,35,13,14,80,7,10,44,10,47,13,11,52,25,24,48,34,12,88,80,33,8,80,45,64,52,79,77 ];
 
var lent=ls.length;
for(var i=0;i<ls.length;i++){
      for(var j=i*2;j<ls.length-2*i;j++){
        if(ls[i*2]>ls[j+1]){
          ls[i*2]=ls[i*2]+ls[j+1];
          ls[j+1]=ls[i*2]-ls[j+1];
          ls[i*2]=ls[i*2]-ls[j+1];
        }//保持内层第一个数为循环最小
         
        if(ls[lent-i*2-1]<ls[lent-j-1]){
          ls[lent-i*2-1]=ls[lent-i*2-1]+ls[lent-j-1];
          ls[lent-j-1]=ls[lent-i*2-1]-ls[lent-j-1];
          ls[lent-i*2-1]=ls[lent-i*2-1]-ls[lent-j-1];
        }////保持内层倒数第一个数为循环最大
           
          if(ls[lent-2-i*2]<ls[lent-j-1]){
            ls[lent-2-i*2]=ls[lent-2-i*2]+ls[lent-j-1];
            ls[lent-j-1]=ls[lent-2-i*2]-ls[lent-j-1];
            ls[lent-2-i*2]=ls[lent-2-i*2]-ls[lent-j-1];
          }//倒数上一个
           
          if(ls[i*2+1]>ls[j+1]){
            ls[i*2+1]=ls[i*2+1]+ls[j+1];
            ls[j+1]=ls[i*2+1]-ls[j+1];
            ls[i*2+1]=ls[i*2+1]-ls[j+1];
          }//下一个
      }
}