집 > 기사 > php教程 > 一个简单的用户反馈表单 (Feedback)

一个简单的用户反馈表单 (Feedback)

PHP中文网원래의: 2016-05-25 17:16:032678검색

feedback.html

<html>

 <head>
  <title>Feedback Form</title>
 </head>

 <body>

 <form action="feedback.php" method="post">
 Name:<input type="text" name="username" size="30">
 <br><br>
 Email:<input type="text" name="useraddr" size="30">
 <br><br>
 <textarea name="comments" cols="30" rows="5">
 </textarea><br>
 <input type="submit" value="Send Form">
 </form>

 </body>

</html>

feedback.php

<?php

$username = $_POST[&#39;username&#39;];
$useraddr = $_POST[&#39;useraddr&#39;];
$comments = $_POST[&#39;comments&#39;];

$to = "php@h.com";  
$re = "Website Feedback";         
$msg = $comments;            

$headers  = "MIME-Version: 1.0\r\n";  
$headers .= "Content-type: text/html; charset=iso-8859-1\r\n";
$headers .= "From: $useraddr \r\n";    
$headers .= "Cc: another@hotmail.com \r\n";

mail( $to, $re, $msg, $headers );      

?>

<html>

 <head>
  <title>Message Received</title>
 </head>

 <body>
 <h3>Thanks for your comments</h3>
 Message received from <?php echo($username); ?><br>
 Reply to <?php echo($useraddr); ?>
 </body>

</html>

성명：

이전 기사：PHP 的 rawurlencode() 和 rawurldecode() 函数다음 기사：基于文件的网页身份认证

一个简单的用户反馈表单 (Feedback)

feedback.html

관련 기사