PHP 날짜로 UNIX 시간 형식을 지정하는 방법

이 기사의 예에서는 PHP 날짜 함수 date를 사용하여 UNIX 시간 형식을 지정하는 방법을 설명합니다. 참고할 수 있도록 모든 사람과 공유하세요. 구체적인 분석은 다음과 같습니다.

날짜 함수는 지정된 형식에 따라 Unix 시간을 원하는 텍스트 출력 형식으로 지정할 수 있습니다

사용된 함수 구문은 다음과 같습니다

string date (string $Format);
string date (string $Format, int $Time);

다음은 데모 코드입니다

<&#63;php
echo "When this page was loaded,\n";
echo 'It was then ', date ('r'), "\n";
echo 'The currend date was ', date ('F j, Y'), "\n";
echo 'The currend date was ', date ('M j, Y'), "\n";
echo 'The currend date was ', date ('m/d/y'), "\n";
echo 'The currend date was the ', date ('jS \o\f M, Y'), "\n";
echo 'The currend time was ', date ('g:i:s A T'), "\n";
echo 'The currend time was ', date ('H:i:s O'), "\n";
echo date ('Y');
date ('L')&#63;(print ' is'):(print ' is not');
echo " a leap year\n";
echo time ('U'), " seconds had elapsed since January 1, 1970.\n";
&#63;>

출력 결과는 다음과 같습니다

It was then Sat, 26 Dec 2009 07:09:51 +0000
The currend date was December 26, 2009
The currend date was Dec 26, 2009
The currend date was 12/26/09
The currend date was the 26th of Dec, 2009
The currend time was 7:09:51 AM GMT
The currend time was 07:09:51 +0000
2009 is not a leap year
1261811391 seconds had elapsed since January 1, 1970.

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